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逆序链表
#include<iostream> using namespace std; class node{ public: node():value(0),next(NULL){} ~node(){} int value; node* next; };///be careful this ; node* createlist(int a[],int n) { node* startnode = new node[n]; node* ret = startnode; for(int i = 0;i<n;i++) { startnode[i].value = a[i]; if(i<n-1) startnode[i].next = startnode + i + 1; } while(startnode) { cout<<" "<<startnode->value; startnode = startnode->next; } cout<<endl; return ret; } node* helper(node* head) { if(head == NULL || head->next == NULL) return head; ///不管以后,只管现在 node* n1 = head; node* n2 = n1->next; head = helper(head->next); n2->next = n1; n1->next = NULL; return head; } int main() { int a[] = {1,2,3,4,5,6,7,8,9}; node * t = createlist(a,9); node* w = helper(t); while(w) {cout<<" "<<w->value; w = w->next; } }
这道题到最后也不是很清楚,所以必须要反复多看看。包裹递归实现和while实现!
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