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【LeetCode】Evaluate Reverse Polish Notation
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +
, -
, *
, /
. Each operand may be an integer or another expression.
Some examples:
["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9 ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6
public class Solution { public int evalRPN(String[] tokens) { Stack<String> stack = new Stack<String>(); if(tokens.length==0) return 0; int[] op = new int[2]; Arrays.fill(op, 0); for(int i=0;i<tokens.length;i++){ if(!tokens[i].equals("+")&&!tokens[i].equals("-")&&!tokens[i].equals("*")&&!tokens[i].equals("/")){ stack.push(tokens[i]); continue; }else{ String operator = tokens[i]; op[1]=Integer.parseInt(stack.peek()); stack.pop(); op[0]=Integer.parseInt(stack.peek()); stack.pop(); int t=0; switch(operator){ case "+":t=op[0]+op[1];break; case "-":t=op[0]-op[1];break; case "*":t=op[0]*op[1];break; case "/":t=op[0]/op[1];break; default:t=0;break; } stack.push(String.valueOf(t)); } } if(stack.isEmpty()||stack.peek().equals("+")||stack.peek().equals("-")||stack.peek().equals("*")||stack.peek().equals("/")) return 0; return Integer.parseInt(stack.peek()); } }
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