首页 > 代码库 > 如何查看db2 产品是否有root 安装的,安装的什么db2的那个产品呢?
如何查看db2 产品是否有root 安装的,安装的什么db2的那个产品呢?
今天看到群友问了两个问题比较基础:
1 怎么确认我的db2是否由root安装的呢?
其实从DB2 UDB V9.1有了db2ls这个命令后,这个问题就简单多了,我们只需要简单的跑下db2ls,然后看输出的Installer UID 是否为0(root uid),如下图所示:
[db2v975@db2udb ~]$ db2ls Install Path Level Fix Pack Special Install Number Install Date Installer UID --------------------------------------------------------------------------------------------------------------------- /opt/ibm/db2/V10.1 10.1.0.2 2 ed Nov 20 02:27:07 2013 PST 0 /opt/ibm/db2/V9.1 9.1.0.8 8 Sun Dec 1 23:14:06 2013 PST 0 /opt/ibm/db2/V9.5 9.5.0.6 6a Sun Dec 1 23:17:40 2013 PST 0 /opt/ibm/db2/V9.7 9.7.0.5 5 Sun Dec 1 23:21:11 2013 PST 0 [db2v975@db2udb install]$ id root uid=0(root) gid=0(root) groups=0(root),1(bin),2(daemon),3(sys),4(adm),6(disk),10(wheel) [db2v975@db2udb install]$
可以看到我虚拟机上的四个db2 都是有root安装的。
2 怎么知道我装的是db2的什么产品(db2 ese,connect,client,aese…etc)呢?
这个问题同样可以用db2ls来解决,这次我们需要用到db2ls的几个参数:
-q
Signifies that the query is to list installed DB2 products and features. By default, only the visible components (features) are displayed unless the -a parameter is also specified.
-p
Lists products only. This will give a brief list of which products the customer has installed rather than listing the features.
-b base-install-path
When using the global db2ls command in /usr/local/bin, you need to specify which directory you are querying. The global db2ls command will simply call the db2ls from that install path and pass in the rest of the parameters.
DB2的db2ls能列指定安装目录下的db2是什么产品。
Example :
[db2v975@db2udb install]$ db2ls -q -p -b /opt/ibm/db2/V10.1 Install Path : /opt/ibm/db2/V10.1 Product Response File ID Level Fix Pack Product Description --------------------------------------------------------------------------------------------------------------------- ENTERPRISE_SERVER_EDITION 10.1.0.2 2 DB2 Enterprise Server Edition [db2v975@db2udb install]$
附:db2ls - List installed DB2 products and features command
http://pic.dhe.ibm.com/infocenter/db2luw/v9r7/index.jsp?topic=%2Fcom.ibm.db2.luw.admin.cmd.doc%2Fdoc%2Fr0023668.html&resultof%3D%2522%2564%2562%2532%256c%2573%2522%2520%2522%2564%2562%2532%256c%2522%2520