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c++继承赋值兼容
其实还是不明白,红色部分,,,求解
#include <iostream>
#include <time.h>
using namespace std;
class B0
{
public:
void display()
{
cout<<"B0::display()"<<endl;
}
};
class B1:public B0
{
public:
void display()
{
cout<<"B1::display()"<<endl;
}
};
class B2:public B0
{
public:
void display()
{
cout<<"B2::display()"<<endl;
}
};
void fun(B0 *ptr)
{
ptr->display();
}
int main()
{
B0 b0;
B1 b1;
B2 b2;
fun(&b0);
fun(&b1);
fun(&b2);
return 0;
}
输出结果都是B0.....
b0=b1;
b0=b2;
结果都是一样的;
想要改变,就要用虚函数或者不要用指针
#include <iostream>
#include <time.h>
using namespace std;
class B0
{
public:
void display()
{
cout<<"B0::display()"<<endl;
}
};
class B1:public B0
{
public:
void display()
{
cout<<"B1::display()"<<endl;
}
};
class B2:public B0
{
public:
void display()
{
cout<<"B2::display()"<<endl;
}
};
int main()
{
B0 b0;
B1 b1;
B2 b2;
b0.display();
b1.display();
b2.display();
b2.B0::display();
return 0;
}
c++继承赋值兼容