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今日已更新 286 篇代码解决方案
by：白书#define M 10000int pre[M],dfs_clock,iscut[M],low[M],bcc_cnt,bccno[M];vector<int>G[M],bcc[M];struct Edge{ int u,v; Edge(int from
https://www.u72.net/daima/ccvv.html - 2024-07-10 22:29:40 - 代码库DescriptionYour city has n junctions. There are mone-way roads between the junctions. As a mayor of the city, you have to ensure the securit
https://www.u72.net/daima/v4d4.html - 2024-07-15 10:41:10 - 代码库Description关系R具有对称性和传递性。数对p q表示pRq,p和q是0或自然数,p不等于q。要求写一个程序将数对序列进行过滤，如果一个数对可以通过前面数对
https://www.u72.net/daima/1ucb.html - 2024-08-30 15:18:19 - 代码库第一种方式：利用java运行时： Java代码 /** * test network * @param ip */ private void getNetworkState(String ip) { Runtime runtime = R
https://www.u72.net/daima/cwke.html - 2024-08-17 18:56:49 - 代码库public bool IsPingOk { get { try { Ping ping = ne
https://www.u72.net/daima/nr650.html - 2024-10-15 09:05:02 - 代码库早上一番捣鼓,把以前丢失的onenote笔记找出来一部分.看到并查集,大二做的笔记,现在已经毫无印象了记得当时看的时候挺费劲,云里雾里的现在再看一遍
https://www.u72.net/daima/nbums.html - 2024-10-03 19:02:39 - 代码库通过前面小节的实践，当前 docker host 的网络拓扑结构如下图所示，今天我们将讨论这几个容器之间的<em>连通</em>性。
https://www.u72.net/daima/nrh66.html - 2024-10-13 02:38:02 - 代码库有向图，不经过重复点的最长链，强<em>连通</em>分量大小不超过5。每个强<em>连通</em>分量内部暴力预处理任意两对点之间的最长路，外面DAG上dp。不是很好写，但是预处理完了之
https://www.u72.net/daima/nvfnf.html - 2024-10-29 07:52:01 - 代码库pid=3861题意：国王要对n个城市进行规划，将这些城市分成若干个城市，强<em>连通</em>的城市必须处于一个州，另外一个州内的任
https://www.u72.net/daima/nnhah.html - 2024-09-19 21:14:37 - 代码库利用bat批处理制作自动ping.bat，测试与多台服务器<em>连通</em>性在Windows Server 2008 和Windows 7 中，PING.EXE的目录是C:
https://www.u72.net/daima/es1c.html - 2024-07-28 11:38:30 - 代码库先上代码：#include <iostream>#include <cstring>#include <vector>#include <stack>using namespace std;int G[1000][1000];int pre[1000],sccno[1000
https://www.u72.net/daima/uufb.html - 2024-07-14 03:35:17 - 代码库NetworkTime Limit: 5000MS Memory Limit: 65536KTotal Submissions: 9434 Accepted: 3511DescriptionA network administrator ma
https://www.u72.net/daima/weeu.html - 2024-08-26 10:51:52 - 代码库C - Network of SchoolsTime Limit:1000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64uSubmit StatusDescriptionA number of school
https://www.u72.net/daima/v9m5.html - 2024-07-15 15:35:45 - 代码库https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=513终于开始接触图了，恩，开始接触DFS了，这道题就
https://www.u72.net/daima/wnhr.html - 2024-08-24 21:27:41 - 代码库给一个有向图，问有多少结点是其他所有结点都可以到达的。等价于，在一个有向无环图上，找出度为0 的结点，如果出度为0的结点只有一个，那么这个就是答案，如果大
https://www.u72.net/daima/c8kc.html - 2024-07-11 11:43:59 - 代码库Caocao‘s BridgesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1499 Accepted S
https://www.u72.net/daima/315z.html - 2024-07-21 10:16:51 - 代码库HDU 3639 Hawk-and-Chicken题目链接题意：就是在一个有向图上，满足传递关系，比如a->b, b->c，那么c可以得到2的支持，问得到支持最大的是谁，并且输出这些人思路：
https://www.u72.net/daima/ezf2.html - 2024-07-28 03:59:15 - 代码库C - Network of SchoolsTime Limit:1000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64uSubmit StatusDescriptionA n
https://www.u72.net/daima/e5hc.html - 2024-09-15 18:47:41 - 代码库DescriptionA number of schools are connected to a computer network. Agreements have been developed among those schools: each school maintain
https://www.u72.net/daima/mbub.html - 2024-07-29 08:50:08 - 代码库POJ 3592 Instantaneous Transference题目链接题意：一个图，能往右和下走，然后有*可以传送到一个位置，‘#‘不能走，走过一个点可以获得该点上面的数字&#20540
https://www.u72.net/daima/ef9z.html - 2024-07-28 09:11:30 - 代码库