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今日已更新 2036 篇代码解决方案
Problem DescriptionDuring summer vacation,Alice stay at home for a long time, with nothing to do. She went out and bought m pokers, tending
https://www.u72.net/daima/sec3.html - 2024-07-13 15:37:05 - 代码库Kingdom of ObsessionTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Problem DescriptionThere is a kind
https://www.u72.net/daima/c98n.html - 2024-08-18 03:50:26 - 代码库对于任何正整数x，其约数的个数记作g(x)。例如g(1)=1、g(6)=4。如果某个正整数x满足：g(x)>g(i) 0<i<x，则称x为反质数。所以，n以内的反质数即为不超过n的约
https://www.u72.net/daima/3180.html - 2024-07-21 10:23:36 - 代码库Saving BeansProblem DescriptionAlthough winter is far away, squirrels have to work day and night to save beans. They need plenty of food to
https://www.u72.net/daima/3s53.html - 2024-07-21 04:49:23 - 代码库Little Hasan loves to play number games with his friends.One day they were playing a game where one of them will speak out a positive number
https://www.u72.net/daima/119m.html - 2024-07-19 08:15:31 - 代码库这么大数的乘法、除法运算，肯定不能先全部乘起来，我的思路是计算出分子、分母上的每个数的个数（因为最大的数为10000，可以开一个数组记录个数）。利用了随机
https://www.u72.net/daima/xun0.html - 2024-07-17 03:08:24 - 代码库Regular PolygonTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 3274 Accepted Sub
https://www.u72.net/daima/eamh.html - 2024-07-28 02:44:38 - 代码库题目大意：给出一棵树，每一个节点有一个权&#20540;，一开始所有节点的权&#20540;都是0。有两种操作，0 x y代表以x为根节点的子树上所有点的权&#20540;增加y。
https://www.u72.net/daima/mn0m.html - 2024-07-29 04:25:40 - 代码库人见人爱A^BTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23657 Accepted Submis
https://www.u72.net/daima/nz839.html - 2024-08-02 05:36:06 - 代码库BiorhythmsTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 115292 Accepted: 36148题目链接：http://poj.org/problem?id=1006DescriptionS
https://www.u72.net/daima/nn52d.html - 2024-08-01 02:04:28 - 代码库Digital RootsTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 79180 Accepted Subm
https://www.u72.net/daima/nvnkn.html - 2024-10-27 19:58:39 - 代码库题目描述为了表彰小联为Samuel星球的探险所做出的贡献，小联被邀请参加Samuel星球近距离载人探险活动。 由于Samuel星球相当遥远，科学家们要在飞船中度过
https://www.u72.net/daima/nc0cw.html - 2024-10-11 02:58:39 - 代码库The Embarrassed CryptographerTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 11978 Accepted: 3194Description
https://www.u72.net/daima/nded4.html - 2024-10-01 23:09:02 - 代码库题意：求组合数C(p, q) / C(r, s)结果保留5为小数。分析：先用筛法求出10000以内的质数，然后计算每个素数对应的指数，最后再根据指数计算答案。 1 #include <
https://www.u72.net/daima/ncna8.html - 2024-08-07 20:48:47 - 代码库输入输出格式输入格式： 第一行为一个正整数 n，表示有 n 组输入数据。接下来的 n 行每行一组输入数据，为四个正整数 a0，a1，b0，b1，每两个整数之间用一个空格
https://www.u72.net/daima/v9m2.html - 2024-08-24 16:40:45 - 代码库Channel AllocationTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 14601 Accepted: 7427DescriptionWhen a radio station is broadcast
https://www.u72.net/daima/d1ev.html - 2024-08-15 08:04:50 - 代码库Strange Way to Express IntegersTime Limit: 1000MS Memory Limit: 131072KTotal Submissions: 9472 Accepted: 2873Description Elina is reading a
https://www.u72.net/daima/d0d7.html - 2024-07-08 03:19:20 - 代码库【题目大意】求2^(2^(2^(2^(2^...)))) mod p。【思路】蒟蒻在知道用欧拉做的前提下，对这题目瞪了好久没有明白，看了正解扑通一声跪下来orz直接搬运popoqq
https://www.u72.net/daima/dcvm.html - 2024-08-15 01:36:46 - 代码库之前看的数论的知识，现在做几道题目找找感觉.....poj 1061 传送门题目大意，给你x，y，m，n，L。代表青蛙a的坐标x，青蛙b的坐标y，青蛙a一次跳的距离m，青蛙b一次跳的
https://www.u72.net/daima/wu0u.html - 2024-07-16 03:31:25 - 代码库X问题Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3295 Accepted Submission(s)
https://www.u72.net/daima/xhca.html - 2024-07-16 20:03:40 - 代码库