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今日已更新 2412 篇代码解决方案
（一）dijkstra，邻接矩阵所有边权均为正，不管有没有环，求单个源点出发，到所有节点的最<em>短路</em>。该方法同时适用于有向图和无向图。
https://www.u72.net/daima/f362.html - 2024-07-10 07:34:18 - 代码库来回最<em>短路</em>问题貌&#20284;也可以用DP来搞，不过拿费用流还是很方便的。可以转化成求满流为2 的最小花费。一般做法
https://www.u72.net/daima/uarr.html - 2024-07-13 17:23:52 - 代码库题意：给定n个点 m条有向边 k下面m条有向边问删最少几个点使得1-n的最<em>短路</em>>k10 11 51 22 33 44 55 102 91 6
https://www.u72.net/daima/z49e.html - 2024-07-05 05:04:55 - 代码库题目链接：http://poj.org/problem?id=1847题意：给了N个交叉口，每个交叉口有自己能转到的交叉口。注意这里：First number in the i-th line, Ki (0 <= Ki <=
https://www.u72.net/daima/nbcb.html - 2024-08-11 13:08:00 - 代码库Bus SystemTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6082 Accepted Submissio
https://www.u72.net/daima/zs4f.html - 2024-07-04 19:41:33 - 代码库题目 一道简单的倒着的floyd。具体可看代码，代码可简化，你有兴趣可以简化一下，就是把那个Dijsktra所实现的功能放到倒着的floyd里面去。 #include<stdio.h
https://www.u72.net/daima/zzf1.html - 2024-07-04 12:07:23 - 代码库链接：http://acm.hust.edu.cn/vjudge/problem/49764分析：多了一个不能连续穿过k个障碍物的限制条件，那么就在状态中增加一个表示已连续穿过cnt个障碍物的
https://www.u72.net/daima/n059.html - 2024-08-11 20:23:14 - 代码库Sparse GraphProblem Description In graph theory, the complement of a graph G is a graph H on the same vertices such that two distinct ver
https://www.u72.net/daima/hdew.html - 2024-08-13 06:27:20 - 代码库这道题主要是要解决以下两个问题： 问题1：给定一个点$x$，如何取出所有经过它的下水道？一条下水道经过$x$等价于它起点在$x$的子树里面且终点不在$x$的子树里
https://www.u72.net/daima/hfb8.html - 2024-08-13 07:27:10 - 代码库Sparse GraphTime Limit: 4000/2000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1563 Accepted Subm
https://www.u72.net/daima/huc2.html - 2024-08-13 10:34:48 - 代码库题目链接：http://61.187.179.132/JudgeOnline/problem.php?id=1491题意：给出一个联通的无向图，边有权值。定义I(v)如下，计算每个点的I值。思路：（1）最简单的就
https://www.u72.net/daima/buze.html - 2024-07-09 00:06:57 - 代码库题目链接：http://61.187.179.132/JudgeOnline/problem.php?id=1003思路：m个点e条边n天。给出每条边的权值以及有些点有些天不能走。对于某连续的两天i和i
https://www.u72.net/daima/bub9.html - 2024-07-09 00:14:15 - 代码库http://acm.xidian.edu.cn/problem.php?id=1078 模版。 #include<iostream>#include<cstring>#include<cstdio>#include<algorithm>#include<
https://www.u72.net/daima/cr63.html - 2024-08-17 16:24:21 - 代码库Domino EffectTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 8224 Accepted: 2068DescriptionDid you know that you can use domino bo
https://www.u72.net/daima/f85v.html - 2024-07-10 11:56:23 - 代码库【题目大意】(2n+1)*(2n+1)的矩形，由里到外每一层都有一个相同的值。问从左上走到右小经过的点累和的最小值。【思路】一眼就是贪心。首先能够想到
https://www.u72.net/daima/fx3x.html - 2024-08-16 23:36:20 - 代码库A Walk Through the ForestTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5421 Ac
https://www.u72.net/daima/r91w.html - 2024-07-12 13:57:21 - 代码库题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=3790Problem Description给你n个点，m条无向边，每条边都有长度d和花费p，给你起点s终点t，要求输出起点
https://www.u72.net/daima/wdcc.html - 2024-07-15 22:05:37 - 代码库Checking an AlibiTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 6217 Accepted: 2257DescriptionA crime has been comitted: a load o
https://www.u72.net/daima/whae.html - 2024-07-15 20:01:20 - 代码库1. What is problem we faced ?/*** Q: What is problem we faced ?** A: In our life, there are many problems about pathfinding. Those
https://www.u72.net/daima/svcc.html - 2024-07-13 03:33:31 - 代码库1 /* 2 题目大意： 3 就是一幢大厦中有0～99的楼层, 然后有1～5个电梯！每个电梯有一定的上升或下降速度和楼层的停止的位置！ 4 问从第0层楼到
https://www.u72.net/daima/w7ef.html - 2024-07-16 13:19:31 - 代码库