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今日已更新 1764 篇代码解决方案
判断两直线p1p2与q1q2是否相交，用向量叉积来判断如果P x Q >0,则P在Q的顺时针方向；如果P x Q <0,则P在Q的逆时针方向；如果P x Q=0,则P与Q共线，可能同向也可
https://www.u72.net/daima/sh0z.html - 2024-07-12 19:46:02 - 代码库题目链接:http://poj.org/problem?id=2777题目意思：就是问你在询问的区间里有几种不同的颜色思路：这题和一般的区间修改差不多，但是唯一不同的就是我们要
https://www.u72.net/daima/vnk0.html - 2024-07-14 18:11:34 - 代码库题目大意：修改树上的节点，然后求子树的和。思路分析：dfs 重新编号，烂大街了。。。#include <cstdio>#include <iostream>#include <cstring>#include <
https://www.u72.net/daima/vses.html - 2024-07-15 03:19:28 - 代码库操作1 的时候标记deng[rt]表示下面一段数都是与当前节点的&#20540;相同下次操作2时直接对有deng标记的节点gcd更新（可能还可以更简单）#include <stdio.h>
https://www.u72.net/daima/vuae.html - 2024-07-15 03:24:00 - 代码库题目大意是说给你一个数组(N个)，没戏可以将其首部的k(k<N)个元素移动至尾部，这样总共会形成N个序列现在要求这n个序列中逆序对数最少的那一个序列有多少
https://www.u72.net/daima/vwev.html - 2024-07-15 05:54:56 - 代码库Wow! Such Sequence!Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2234 Accepte
https://www.u72.net/daima/vwe0.html - 2024-07-15 05:55:07 - 代码库DescriptionRailway tickets were difficult to buy around the Lunar New Year in China, so we must get up early and join a long queue…The Luna
https://www.u72.net/daima/vxf2.html - 2024-07-15 06:16:05 - 代码库Problem DescriptionRecently, Doge got a funny birthday present from his new friend, Protein Tiger from St. Beeze College. No, not cactuses.
https://www.u72.net/daima/vkfa.html - 2024-07-14 21:18:13 - 代码库之前一篇文章里写了一种差乘判断方法：http://www.cnblogs.com/hont/p/6105997.html bool IsIntersection(Vector3 a, Vector3 b, Vector3 c, Vect
https://www.u72.net/daima/vffs.html - 2024-08-23 13:48:15 - 代码库HDU 1754 单点更新，区间查询最大&#20540;，水题……#include<iostream>#include<cstdio>#include<cstring>#include<algorithm>#include<map>#includ
https://www.u72.net/daima/vhxx.html - 2024-07-14 20:40:19 - 代码库题目链接：http://poj.org/problem?id=2182Lost CowsTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 9152 Accepted: 5879DescriptionN (2
https://www.u72.net/daima/vh83.html - 2024-07-14 20:57:31 - 代码库囧，一开始看错题意，后来才发现人是垂直下落的，被附带链接里的Man Down游戏误导了。那就变成了一个简单的DAG模型动态规划，随意搞就ok了#include <cstdio>#i
https://www.u72.net/daima/1zwx.html - 2024-07-18 18:45:15 - 代码库题意：给定n长的序列 m个操作序列默认为 1, 2, 3···n操作1：D [l,r] 把[l,r]区间增长 ：（ 1,2,3,4 进行 D [1,3]变成 1,1,2,2,3,3,4 ）操作2：Q [l,r] 问区间[l
https://www.u72.net/daima/1kfa.html - 2024-07-18 20:15:23 - 代码库这个网上一搜一大堆，就是先求一个，其余的for一遍搞出来。#include<stdio.h>#include<stdlib.h>#define max 5555int sum[max * 4];int min(int a, in
https://www.u72.net/daima/1k6r.html - 2024-07-18 20:47:57 - 代码库#include <cstdio>#include <cstring>#include <algorithm>#include <climits>#include <string>#include <iostream>#include <map>#include <cstdlib
https://www.u72.net/daima/1k6v.html - 2024-07-18 20:48:10 - 代码库这题不说了，都是泪。这题也是拆点。#include <cstdio>#include <cstring>#include <algorithm>#include <climits>#include <string>#include <iost
https://www.u72.net/daima/1k60.html - 2024-07-18 20:48:20 - 代码库直接暴力更新，复杂度10NlogN#include <cstdio>#include <cstring>#include <iostream>#include <map>#include <set>#include <vector>#include <string
https://www.u72.net/daima/1n3n.html - 2024-07-18 18:03:19 - 代码库Nowadays it is becoming increasingly difficult to park a car in cities successfully. Let‘s imagine a segment of a street as long as L meter
https://www.u72.net/daima/305s.html - 2024-07-21 09:24:23 - 代码库Language:DefaultLost CowsTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 9207 Accepted: 5922DescriptionN (2 <= N <= 8,000) cows ha
https://www.u72.net/daima/3xmz.html - 2024-07-21 08:43:59 - 代码库Problem DescriptionIn the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made up o
https://www.u72.net/daima/x4k5.html - 2024-07-17 10:08:47 - 代码库