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今日已更新 5390 篇代码解决方案
PieTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 9653 Accepted: 3478 Special JudgeDescriptionMy birthday is coming up and tradit
https://www.u72.net/daima/ncuu.html - 2024-07-03 17:19:08 - 代码库Fire stationTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1308 Accepted Submi
https://www.u72.net/daima/ru9.html - 2024-07-02 12:42:07 - 代码库List wants to travelTime Limit: 6000/3000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 429 Accept
https://www.u72.net/daima/kzza.html - 2024-08-14 00:03:46 - 代码库// 时间let date = new Date();debugger;let seperator1 = "-";let seperator2 = ":";let month = date.getMonth() + 1;let strDate = date.get
https://www.u72.net/daima/kur7.html - 2024-08-14 07:13:06 - 代码库没负环。直接搞就行，但是 spfa 队列会超时。 ? 1 2 3 4 5 6 7 8 9 10 11 12
https://www.u72.net/daima/k130.html - 2024-07-07 04:31:08 - 代码库题意：给出一个n*m的矩阵，内有一些数字。当你从一个方格走到另一个方格时，按这两个方格数字的大小，有（升，平，降）三种费用。你需要在矩阵中找到边长大于2的一个矩
https://www.u72.net/daima/k69h.html - 2024-07-07 09:03:24 - 代码库dd命令：convert and copy a file 用法： dd if=/PATH/FROM/SRC of=/PATH/TO/DEST bs=#：block size, 复制单元大小； count=#：复制多少
https://www.u72.net/daima/cazc.html - 2024-08-17 09:03:30 - 代码库这题我的代码 还没有在OJ上提交 因为 我们的Oj 又崩溃了=-= touch me=他好了 就去交了 但应该是对的了 因为 大神帮我解决了那个死循环问题l = mid+
https://www.u72.net/daima/few4.html - 2024-07-10 13:31:19 - 代码库IntervalsTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 20779 Accepted: 7863DescriptionYou are given n closed, integer intervals
https://www.u72.net/daima/bn3w.html - 2024-07-08 15:42:19 - 代码库LayoutTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 6574 Accepted: 3177DescriptionLike everyone else, cows like to stand close t
https://www.u72.net/daima/bn6z.html - 2024-07-08 15:47:08 - 代码库http://acm.xidian.edu.cn/problem.php?id=1023 因为区间不重复，所以就好办了。把l和r、id分开保存，排序后下标还是对应的，偷懒直接用lowerbound解决。
https://www.u72.net/daima/fxnh.html - 2024-08-16 23:06:03 - 代码库最近在学习android内核漏洞，写篇博做个记录，也算是所学即用。 https://www.codeaurora.org/multiple-memory-corruption-issues-write-operation-qdsp6v2
https://www.u72.net/daima/durb.html - 2024-08-15 03:46:44 - 代码库const int maxn = 10010;int vis[maxn];int y[maxn];vector <int> G[maxn];int n;bool dfs(int u){ for(int i = 0; i < G[u].size(); i++)
https://www.u72.net/daima/dw3n.html - 2024-07-08 02:00:00 - 代码库题目真是不好读，大意如下（知道题意就很好解了）大致题意：一条河长度为 L，河的起点(Start)和终点(End)分别有2块石头，S到E的距离就是L。河中有n块石头，每块石头
https://www.u72.net/daima/fddz.html - 2024-07-09 19:29:29 - 代码库const int MAX = 1e6+10;const int inf = 0x3f3f3f3f;int n,m;int lx[MAX],ly[MAX];int match[MAX];int usex[MAX],usey[MAX];int w[MAX][MAX];
https://www.u72.net/daima/fr96.html - 2024-07-09 23:40:45 - 代码库链接： http://acm.hrbust.edu.cn/index.php?m=ProblemSet&a=showProblem&problem_id=1584Description青蛙王国一年一度的游戏又开始了，这个游戏要求青
https://www.u72.net/daima/k8ru.html - 2024-07-07 10:24:43 - 代码库http://acm.hdu.edu.cn/showproblem.php?pid=4717大致题意：给出每个点的坐标以及每个点移动的速度和方向。问在那一时刻点集中最远的距离在所有时刻的
https://www.u72.net/daima/cu6e.html - 2024-07-11 01:24:28 - 代码库本文档以smdk2410为例初步分析了u-boot-2014.04的配置、启动流程、代码重定向、内存分布。 u-boot-2014.04这个版本的uboot从Linux内核中借鉴了很多东
https://www.u72.net/daima/d700.html - 2024-07-08 10:05:35 - 代码库IntervalsTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 20786 Accepted: 7866DescriptionYou are given n closed, integer intervals
https://www.u72.net/daima/bxuh.html - 2024-07-09 02:59:03 - 代码库#include<stdio.h>void binary_search(int key, int a[], int n) /*自定义函数binary_search*/{ int low, high, mid, count = 0, count1 = 0; l
https://www.u72.net/daima/b653.html - 2024-08-16 08:17:50 - 代码库