<span style="background-color: rgb(255, 204, 204);">// 功能包括基础地图 定位 线路规划 POI线路检索</span><span style="background-color: rgb(2
https://www.u72.net/daima/nkme5.html - 2024-08-04 15:09:46 - 代码库一、替换字符 题目:请实现一个函数,把字符串中的每个空格替换成“%20”。例如输入“We are happy.”,则输出“We%20are%20
https://www.u72.net/daima/nc8x1.html - 2024-08-08 17:49:01 - 代码库#include<cstdio>#include<iostream>#include<queue>#include<map>#include<stack>#include<string>using namespace std;priority_queu
https://www.u72.net/daima/nc9ku.html - 2024-10-12 06:24:39 - 代码库都从1开始计数。高度从下往上数。深度从上往下数。对于整棵树来说,最深的叶结点的深度就是树的深度;树根的高度就是树的高度。这样树的高度和深度是相
https://www.u72.net/daima/nc91a.html - 2024-10-12 07:47:02 - 代码库#include<cstdio>#include<cstring>int book[205];int buf[205];int main(){ int n,m; int tmp; while(scanf("%d %d",&n,&m)!=E
https://www.u72.net/daima/nc6va.html - 2024-10-11 21:57:39 - 代码库#include<cstdio>#include<stack>using namespace std;char str[110];char res[110];int main(){ while(scanf("%s",str)!=EOF){
https://www.u72.net/daima/nc6wm.html - 2024-10-11 22:12:02 - 代码库题目链接地址:http://ac.jobdu.com/problem.php?pid=1146转载请注明本文地址http://blog.csdn.net/yangnanhai93/article/details/42014265因为问题只要
https://www.u72.net/daima/nceu6.html - 2024-08-08 19:30:33 - 代码库0是NULL的一个实现,但NULL不是0。指针的数值是其所指向的内存的地址。很多时候我们需要标明“这个指针当前为无效指针,它不指向任何可以使用的内存空
https://www.u72.net/daima/nceva.html - 2024-10-12 10:22:38 - 代码库while(getline(cin,s),s!="0")逗号表达式,返回的是s!="0"题目输入的最后一组数据是0 #include<cstdio>#include<iostream>#include<queue>
https://www.u72.net/daima/nc8fb.html - 2024-10-12 03:36:02 - 代码库简单hash #include<cstdio>#include<cstring>int grade[101];int main(){ int n; int x; while(scanf("%d",&n)!=EOF){ if(
https://www.u72.net/daima/nc2v6.html - 2024-10-11 09:43:39 - 代码库#include<cstdio>#include<cstring>#define offset 500000bool isinput[1000001];int main(){ int n,m; while(scanf("%d %d",&n,&m)
https://www.u72.net/daima/nc209.html - 2024-10-11 10:05:02 - 代码库#include<cstdio>int main(){ int h; scanf("%d",&h); int blanks; int num; for(int i=0;i<h;i++){ num=h+i*2;
https://www.u72.net/daima/nc29h.html - 2024-10-11 11:01:02 - 代码库#include<cstdio>#include<cstring>int buf[205];int main(){ int n; int x; while(scanf("%d",&n)!=EOF){ for(int i=
https://www.u72.net/daima/nc2ma.html - 2024-10-11 11:13:39 - 代码库题目描述: 用小于等于n元去买100只鸡,大鸡5元/只,小鸡3元/只,还有1/3元每只的一种小鸡,分别记为x只,y只,z只。编程求解x,y,z所有可能解。输入: 测试数
https://www.u72.net/daima/nc5kx.html - 2024-08-08 14:22:56 - 代码库先排版,再输出。先定位中心坐标,然后定位左上角坐标,然后开始排版,四边同步。左上角起始为(1,1) .#include<cstdio>char output[85][85];int main(){
https://www.u72.net/daima/nc2ms.html - 2024-10-11 11:16:02 - 代码库贪心,每次选择浓度最低的。注意浮点数比较的问题。AC如下:#include<cstdio>#include<algorithm>#include<cmath>using namespace std;int buf[
https://www.u72.net/daima/nc5mf.html - 2024-10-11 20:28:39 - 代码库#include<cstdio>int buf[105];int main(){ int n; int num; bool isfirst; scanf("%d",&n); while(n--){ scanf(
https://www.u72.net/daima/nc5u0.html - 2024-10-11 18:44:39 - 代码库#include<cstdio>int buf[105];int main(){ int n,m; while(scanf("%d",&n)!=EOF){ for(int i=0;i<n;i++) scanf("%d",&buf[i]);
https://www.u72.net/daima/nc50h.html - 2024-10-11 19:09:39 - 代码库#include<cstdio>#include<algorithm>using namespace std;struct Program{ int s; int e; bool operator < (const Program &A)
https://www.u72.net/daima/nc549.html - 2024-10-11 19:43:39 - 代码库#include<cstdio>#include<algorithm>using namespace std;const double eps=1e-8;bool greater(double x){ if(x>eps) return 1; el
https://www.u72.net/daima/nc565.html - 2024-10-11 19:56:01 - 代码库