原文:经典算法题每日演练——第八题 AC自<em>动机</em> 上一篇我们说了单模式匹配算法KMP,现在我们有需求了,我要检查一篇文章中是否有某些敏感词,这其实就是
https://www.u72.net/daima/nws8v.html - 2024-11-06 03:20:02 - 代码库我们要修改软件,万变不离其宗,无非就是四种<em>动机</em>:1.增加新功能;2.原有功能
https://www.u72.net/daima/c4h9.html - 2024-07-11 08:06:03 - 代码库pid=3796 AC自<em>动机</em>模板注意如果有重复字符串,要输出所有的重复
https://www.u72.net/daima/nbwkv.html - 2024-10-03 22:52:39 - 代码库hdu 5955 Guessing the Dice Roll 【AC自<em>动机</em>+高斯消元】题意:给出 n&le;10 个长为 L&le;10 的串,
https://www.u72.net/daima/nub0d.html - 2024-10-22 08:40:02 - 代码库转载请注明出处:http://www.cnblogs.com/kirai/ 作者:Kirai零.问题的提出 最近希望在分布式平台上实现一个AC自<em>动机</em>,但是如何在这样的分布式平台上
https://www.u72.net/daima/evuv.html - 2024-09-15 06:54:53 - 代码库将p个不能包含的字符串建立AC自<em>动机</em>,每个结
https://www.u72.net/daima/7vch.html - 2024-07-25 09:54:12 - 代码库这个还是给个例子比较形象:模式串:she,shr,her,say目标串:yasherhs。出现了两个。主要是fail指针求解。 1 #include<iostream> 2 #include<string> 3 #
https://www.u72.net/daima/nc8v.html - 2024-08-11 15:06:11 - 代码库hdu2222 字符串多模匹配算法 采用kuangbin模板#include <stdio.h>#include <algorithm>#include <iostream>#include <string.h>#include <queue>
https://www.u72.net/daima/zrz5.html - 2024-07-04 18:15:45 - 代码库ZOJ 3430 Detect the Virus挺扯的一个题,解码有点问题+注意用int存,跟HDU2222差不多...#include <iostream>#include <cstring>#include <cstdio>#i
https://www.u72.net/daima/zzwk.html - 2024-07-04 12:17:27 - 代码库#include<stdio.h>#define N 30char str[N]={NULL};void Print(int i,char y);int st[N];int t=0,k=0;struct node//定义一个队列{ char d
https://www.u72.net/daima/w23a.html - 2024-08-25 22:18:14 - 代码库#include <stdio.h> //s为初态,z为终态 int in(int s,int z){ if(s == z) { printf("\n这个状态属于 Z"); return 1;
https://www.u72.net/daima/um10.html - 2024-08-23 02:10:55 - 代码库#include <stdio.h> //s为初态,z为终态int in(int s,int z){ if(s == z) { printf("3\nlook!the last status belon
https://www.u72.net/daima/vza5.html - 2024-08-23 05:50:38 - 代码库#include<string.h>#include<stdio.h>#include<stdlib.h>int main(){ char p[30][30]; char q[30][30]; int line=0; int n;
https://www.u72.net/daima/vzn8.html - 2024-08-23 05:54:45 - 代码库#include<stdio.h>#define MAX 20main(){ int i=0,j=0,k,l,m,n,number; char ch; char a[MAX][MAX]; printf("请输入正规式:");
https://www.u72.net/daima/x248.html - 2024-08-27 15:20:13 - 代码库#include<stdio.h>#define N 30char str[N]={NULL};int st[N];int t=0,k=0,a,t1=0;struct node//定义一个队列{ char data; struct nod
https://www.u72.net/daima/x64s.html - 2024-08-27 21:24:58 - 代码库BZOJ3998#include <cstdio>#include <cstring>using namespace std; int last,dis[1000011],fa[1000011],a[1000011][26],cnt,sum[1000011];
https://www.u72.net/daima/3zh5.html - 2024-09-02 10:45:16 - 代码库#include<stdio.h>main(){ int i=0,j=0,x=0,y; int number=2; int count=0; char ch; char a[100][100]; printf("请输入
https://www.u72.net/daima/xvah.html - 2024-08-27 06:46:12 - 代码库解决字符串问题 1 #include <stdio.h> 2 #include <algorithm> 3 #include <iostream> 4 #include <string.h> 5 #include <queue> 6 using name
https://www.u72.net/daima/nz8vn.html - 2024-09-22 22:44:37 - 代码库#include<cstdio>#include<cstring>#include<iostream>#include<algorithm>#define L 51#define LL 100000002using namespace std;char c[11]
https://www.u72.net/daima/nsvws.html - 2024-10-17 15:19:01 - 代码库题目链接:hdu_2825_Wireless Password题意:给你m个串,问长度为n至少含k个串的字符串有多少个题解:设dp[i][j][k]表示考虑到长度为i,第j个自<em>动机</em>的节点
https://www.u72.net/daima/8rm.html - 2024-08-11 05:35:09 - 代码库