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Project Euler 26 计算小数位循环的位数
A unit fraction contains 1 in the numerator. The decimal representation of the unit fractions with denominators 2 to 10 are given:
1/2 = 0.5 1/3 = 0.(3) 1/4 = 0.25 1/5 = 0.2 1/6 = 0.1(6) 1/7 = 0.(142857) 1/8 = 0.125 1/9 = 0.(1) 1/10 = 0.1
Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle. It can be seen that 1/7 has a 6-digit recurring cycle.
Find the value of d < 1000 for which 1/d contains the longest recurring cycle in its decimal fraction part.
解析:费马小定理的应用
def recu_cycle(d): for t in range(1,d): if 1 == 10**t % d: return t; return 0 longest = max(recu_cycle(i) for i in range(2,1001)) print [i for i in range(2,1001) if recu_cycle(i) == longest][0]
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