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链表(裸题)
Doubly Linked List Aizu - ALDS1_3_C
Your task is to implement a double linked list.
Write a program which performs the following operations:
- insert x: insert an element with key x into the front of the list
- delete x: delete the first element which has the key of x from the list
- deleteFirst: delete the first element from the list
- deleteLast: delete the last element from the list
Input
The input is given in the following format:
n
command1
command2
...
commandn
In the first line, the number of operations n is given. In the following n lines, the above mentioned operations are given in the following format:
- insert x
- delete x
- deleteFirst
- deleteLast
Output
Print all the element (key) in the list after the given operations. Two consequtive keys should be separated by a single space.
Constraints
- The number of operations ≤ 2,000,000
- The number of delete operations ≤ 20
- 0 ≤ value of a key ≤ 109
- the number of elements in the list does not exceed 106
Sample Input 1
7 insert 5 insert 2 insert 3 insert 1 delete 3 insert 6 delete 5
Sample Output 1
6 1 2
Sample Input 2
9 insert 5 insert 2 insert 3 insert 1 delete 3 insert 6 delete 5 deleteFirst deleteLast
Sample Output 2
1
题目意思是指写一个支持插入元素,删除特定元素,删除头元素,删除尾元素,打印整条链表操作的链表。
下面是初始化操作:
然后是各种普通操作顺序:
在理解后就可以看代码了,本题为了快速的删除尾,所使用的是环型链表,上代码:
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cstdlib> 5 using namespace std; 6 7 struct Node{ 8 int key; 9 Node *prev; 10 Node *next; 11 }; 12 13 Node *head; 14 15 Node *listSearch(int key){ 16 Node *cur = head->next; 17 while(cur != head && cur->key != key){ 18 cur = cur->next; 19 } 20 return cur; 21 } 22 23 void init(){ 24 head = new Node; 25 head->prev = head; 26 head->next = head; 27 } 28 29 void printlist(){ 30 Node *cur = head->next; 31 int isf = 0; 32 while(1){ 33 if(cur == head)break; 34 if(isf++ > 0)printf(" "); 35 printf("%d",cur->key); 36 cur = cur->next; 37 } 38 printf("\n"); 39 } 40 41 void insert(int key){ 42 Node *x = new Node; 43 x->key = key; 44 x->next = head->next; 45 head->next->prev = x; 46 head->next = x; 47 x->prev = head; 48 } 49 50 void deleteNode(Node *t){ 51 if(t == head)return; 52 t->prev->next = t->next; 53 t->next->prev = t->prev; 54 free(t); 55 } 56 57 void deleteFirst(){ 58 deleteNode(head->next); 59 } 60 61 void deleteLast(){ 62 deleteNode(head->prev); 63 } 64 65 void deletekey(int key){ 66 deleteNode(listSearch(key)); 67 } 68 69 int main(){ 70 int key,n,i; 71 char com[20]; 72 scanf("%d",&n); 73 init(); 74 for(i = 0;i < n; i++){ 75 scanf("%s%d",com,&key); 76 if(com[0] == ‘i‘){insert(key);} 77 else if(com[0] == ‘d‘){ 78 if(strlen(com) > 6){ 79 if(com[6] == ‘F‘)deleteFirst(); 80 else if(com[6] == ‘L‘)deleteLast(); 81 } 82 else{ 83 deletekey(key); 84 } 85 } 86 } 87 printlist(); 88 return 0; 89 }
链表(裸题)
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