Sum Root to Leaf Numbers

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1   /   2   3

The root-to-leaf path 1->2 represents the number 12. The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

思想： 分三种情况： 1. 当前结点为空，返回0.  2. 叶子结点， 返回当前值.  3. 父结点，返回左右两个 path 值的和。

/** * Definition for binary tree * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ int dfs(TreeNode *root, int sum) {    if(root == 0) return 0;    sum = sum * 10 + root->val;    if(root->left || root->right)         return dfs(root->left, sum) + dfs(root->right, sum);    return sum; }class Solution {public:    int sumNumbers(TreeNode *root) {        return dfs(root, 0);    }};

23. Sum Root to Leaf Numbers