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[leetcode]Sum Root to Leaf Numbers
Sum Root to Leaf Numbers
Given a binary tree containing digits from
0-9
only, each root-to-leaf path could represent a number.An example is the root-to-leaf path
1->2->3
which represents the number123
.Find the total sum of all root-to-leaf numbers.
For example,
1 / 2 3
The root-to-leaf path
1->2
represents the number12
.
The root-to-leaf path1->3
represents the number13
.Return the sum = 12 + 13 =
25
.
算法思路:
DFS。
代码如下:
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */10 public class Solution {11 int res = 0;12 public int sumNumbers(TreeNode root){13 if(root == null) return res;14 dfs(root,0);15 return res;16 }17 private void dfs(TreeNode root,int num){18 if(root == null) return;19 if(root.left == null && root.right == null){20 res += 10 * num + root.val;21 return;22 }23 num = num * 10 + root.val;24 if(root.left != null){25 dfs(root.left,num);26 }27 if(root.right != null){28 dfs(root.right,num);29 }30 }31 32 }
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