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leetcode--Sum Root to Leaf Numbers
Given a binary tree containing digits from 0-9
only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3
which represents the number 123
.
Find the total sum of all root-to-leaf numbers.
For example,
1 / 2 3
The root-to-leaf path 1->2
represents the number 12
.
The root-to-leaf path 1->3
represents the number 13
.
Return the sum = 12 + 13 = 25
.
?
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 | /** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { /**This problem is just an implementation of bfs<br> *The algorithm is straightforward:<br> * @author Averill Zheng * @version 2014-06-02 * @since JDK 1.7 */ public int sumNumbers(TreeNode root) { int sum = 0 ; Queue<TreeNode> node = new LinkedList<TreeNode>(); Queue<Integer> number = new LinkedList<Integer>(); if (root != null ){ node.add(root); number.add(root.val); while (node.peek() != null ){ TreeNode aNode = node.poll(); int num = number.poll(); if (aNode.left != null ){ node.add(aNode.left); number.add(num * 10 +aNode.left.val); } if (aNode.right != null ){ node.add(aNode.right); number.add(num * 10 +aNode.right.val); } if (aNode.left == null && aNode.right == null ){ sum += num; } } } return sum; } } |
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