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Codeforces Round #263 (Div. 2) proB

2024-07-19 17:51:17   222人阅读

题目：

B. Appleman and Card Game
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Appleman has n cards. Each card has an uppercase letter written on it. Toastman must choose k cards from Appleman‘s cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman‘s card i you should calculate how much Toastman‘s cards have the letter equal to letter on ith, then sum up all these quantities, such a number of coins Appleman should give to Toastman.

Given the description of Appleman‘s cards. What is the maximum number of coins Toastman can get?

Input

The first line contains two integers n and k (1?≤?k?≤?n?≤?105). The next line contains n uppercase letters without spaces — the i-th letter describes the i-th card of the Appleman.

Output

Print a single integer – the answer to the problem.

Sample test(s)
input
15 10
DZFDFZDFDDDDDDF
output
82
input
6 4
YJSNPI
output
4
Note

In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin.


题意分析：

n张卡片，可以选取k张。可以得的分数是卡数的平分，求最大分数。
贪心吧，对字符进行记录，然后按个数排序。注意使用long long cha得残暴又是万恶的 long long

代码：

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
char s[110000];
int j[500],cn[500];
void solve()
{
    int n,k;
    long long ans=0;
    scanf("%d%d",&n,&k);
    scanf("%s",s);
    int len=strlen(s);
    for(int i=0; i<len; i++)
    {
        j[s[i]]++;
    }
    while(k)
    {
        k--;
        int w=0,Max=0;
        for(int i='A'; i<='Z'; i++)
        {
            if(j[i]>Max&&cn[i]<j[i])
            {
                Max=j[i];
                w=i;
            }
        }
        cn[w]++;
    }
    for(int i='A'; i<='Z'; i++)
    {
        ans+=1LL*cn[i]*cn[i];
    }
    cout<<ans<<endl;
}
int main()
{
    solve();
    return 0;
}



Codeforces Round #263 (Div. 2) proB


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