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采集元数据的C++实现
我要做的是提取Test_case的名字，以及Test_case的持续时间（单位秒）：下面是一段示例元数据
Start| 20140618 root (6033) | tpi 1.4 | 14:53:52 10050943579848 0 | Start| 20814 SunOS 5.11 11.2 i86pc tcx4440-01 | STF_ENV| STC_NAME = os-zones | STF_ENV| STC_VERSION = 2.10.0 | STF_ENV| STC_OS_VERSION = 5.11 | STF_ENV| STF_EXECUTE_MODE = ipkg:amd64 | STF_ENV| cwd = /opt/stc/suites/os/zones/tests/os/functional | Test_Case_Start| 20858 tests/os/functional/setup | 14:53:52 10051107110387 0 | stdout| stdout| 14:53:53 SUCCESS: zone_is_running zone2 stdout| zone 'zone2' is running stdout| stdout| 14:53:53 SUCCESS: zone_is_running zone1 stdout| zone 'zone1' is running stdout| 14:53:53 zones 'zone2 zone1 ' are running Test_Case_End| 20858 tests/os/functional/setup | PASS | 14:53:53 10052165298138 0 |
我想要得到的结果是：
tests/os/functional/setup 1
由于我的元数据比较小(不会超过20MB，所以我选择用vector)，源代码如下：
#include <iostream>
#include <vector>
#include <string>
#include <fstream>
#include <cstdlib>
using namespace std;
/*
* There are not split function, you should add one by yourself
*/
vector<string> split(const string &str, string pattern){
string :: size_type pos;
vector <string> result;
int size = str.size();
int i = 0;
for(i = 0; i < size; i++){
pos = str.find(pattern, i);
if(pos < size){
string subStr = str.substr(i, pos - i);//substr(beginPosition, length)
//cout<<"i = "<<i<<" ,pos - 1 = "<<pos - 1<<endl;
//cout<<str.substr(i, pos - i)<<endl;
result.push_back(subStr);
i = pos + pattern.size() - 1;
//cout<<subStr<<endl;
//cout<<"i="<<i<<endl;
}
}
return result;
}
/*
* Duration Time = endTime - startTime
* eg: Duration Time = 1:10:08 - 23:08:08 = (25 * 3600 + 10 * 60 + 8) - (23 * 3600 + 8 * 60 + 7)
*/
int getDurationTime(string startTime, string endTime){
vector<string> startTimeVector;
vector<string> endTimeVector;
int startTimeSeconds = 0;
int endTimeSeconds = 0;
startTime = startTime+":";//1:10:08 , if we do not add ":", we can not get 08
endTime = endTime + ":";
endTimeVector = split(endTime, ":");
startTimeVector = split(startTime, ":");
startTimeSeconds = atoi(startTimeVector[0].c_str()) * 3600 + atoi(startTimeVector[1].c_str()) * 60 + atoi(startTimeVector[2].c_str());
endTimeSeconds = atoi(endTimeVector[0].c_str()) * 3600 + atoi(endTimeVector[1].c_str()) * 60 + atoi(endTimeVector[2].c_str());
if(endTimeSeconds < startTimeSeconds) {
endTimeSeconds = endTimeSeconds + 24 * 3600;
}
// cout<<"endTimeSeconds:"<<endTimeSeconds << " startTimeSeconds:"<<startTimeSeconds<<endl;
// cout<<endTimeSeconds - startTimeSeconds<<endl;
return endTimeSeconds - startTimeSeconds;
}
int main()
{
vector< pair<string, int> > caseDurationVec;
string journalInput = "journal.base";
string journalOutput = "journal.base.out";
ifstream infile(journalInput.c_str());
ofstream outfile(journalOutput.c_str());
string buffer;
const string Case_Start = "Test_Case_Start";
const string Case_End = "Test_Case_End";
int i = 0;
vector<string> resultVec;
string caseStartTime = "";
string caseEndTime = "";
while(getline(infile, buffer)){
if(buffer.find(Case_Start) != buffer.npos){
resultVec = split(buffer," ");
caseStartTime = resultVec[4];
}
if(buffer.find(Case_End) != buffer.npos){
resultVec = split(buffer," ");
caseEndTime = resultVec[6];
caseDurationVec.push_back(make_pair<string, int>(resultVec[2], getDurationTime(caseStartTime, caseEndTime)));
cout<<"There are "<<i++<<"cases"<<endl;
}
}
vector< pair<string, int> > :: iterator iter;
for(iter = caseDurationVec.begin(); iter != caseDurationVec.end(); iter++)
{
outfile<<iter->first<<" "<<iter->second<<endl;
}
infile.close();
outfile.close();
//system("pause");
return 1;
}采集元数据的C++实现
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