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Codeforces46D--区间查询

#include <stdio.h>#include <stdlib.h>#include <math.h>#include <time.h>#include <string.h>#include <iostream>#include <vector>#include <list>#include <stack>#include <queue>#include <map>#include <set>#include <algorithm>typedef short int int16;///32767typedef int int32;///2147483647typedef long long int64;///9223372036854775807const double PI=acos(-1.0);///3.141593const long long MOD=(long long)1E9+7LL;///1000000007int isdigit(int c);int islower(int c);int isupper(int c);int tolower(int c);int toupper(int c);template <class T> T Susake_pow(T a,T b)///pow{T res;if(b==0) return 1;else while((b&1)==0){b>>=1;a*=a;}res=a;b>>=1;while(b!=0){a*=a;if((b&1)!=0)res*=a;b>>=1;}return res;}template<class T> inline T gcd(T a,T b)///gcd{if(a<0)return gcd(-a,b);if(b<0)return gcd(a,-b);return (b==0)?a:gcd(b,a%b);}template<class T> inline T lcm(T a,T b)///lcm{if(a<0)return lcm(-a,b);if(b<0)return lcm(a,-b);return a*(b/gcd(a,b));}template<class T> inline char *Susake_nsystem(T n)///itoa(26){T t=0,i;char *s,*p;s=(char *)malloc(sizeof(char)*1000);p=(char *)malloc(sizeof(char)*1000);while(n){s[t]=n%26+64;if(s[t]==64){s[t]+=26;n-=26;}t++;n/=26;}s[t]=\0;for(i = 0; i < t; i++)p[i]=s[t-1-i];p[i]=\0;free(s);return p;}int Susake_system(char *s)///atoi(26){int len=strlen(s),i,sum=0;char p[1000];for(i=0;i<len;i++)p[i]=s[len-1-i]-64;for(i=0;i<len;i++)sum+=p[i]*Susake_pow(26,i);return sum;}int fa[1];template <class T> T union_find(T x)///union_find{return fa[x] == x ? x : fa[x] = union_find(fa[x]);}const int INF = 1000000000;int main() {    int L, B, F, n, a[128], b[128];    std::pair<int, int> p[128];    std::vector<std::pair<int, int> > v;    scanf("%d%d%d", &L, &F, &B);    v.push_back(std::make_pair(-INF, -F));    v.push_back(std::make_pair(L + B, INF));    scanf("%d", &n);    for (int i = 1; i <= n; ++i) {        scanf("%d%d", &a[i], &b[i]);        if (a[i] == 2) {            v.erase(find(v.begin(), v.end(), p[b[i]]));        } else {            p[i].first = -1;            for (int j = 1; j < (int)v.size(); ++j) {                if (v[j - 1].second + F + b[i] + B <= v[j].first) {                    p[i] = std::make_pair(v[j - 1].second + F, v[j - 1].second + F + b[i]);                    v.push_back(p[i]);                    sort(v.begin(), v.end());                    break;                }            }            printf("%d\n", p[i].first);        }    }    return 0;}

 

Codeforces46D--区间查询