首页 > 代码库 > POJ 2018 Best Cow Fences
POJ 2018 Best Cow Fences
斜率优化。
#pragma comment(linker, "/STACK:1024000000,1024000000")#include<cstdio>#include<cstring>#include<cmath>#include<algorithm>#include<vector>#include<map>#include<set>#include<queue>#include<stack>#include<ctime>#include<iostream>using namespace std;typedef long long LL;const double pi=acos(-1.0),eps=1e-10;void File(){ freopen("D:\\in.txt","r",stdin); freopen("D:\\out.txt","w",stdout);}template <class T>inline void read(T &x){ char c = getchar(); x = 0; while(!isdigit(c)) c = getchar(); while(isdigit(c)) { x = x * 10 + c - ‘0‘; c = getchar(); }}int n,k;double a[100010],s[100010];int q[100010],f1,f2;bool delete1(int a,int b,int c){ if((s[c]-s[a])*(c-b)<(s[c]-s[b])*(c-a)) return 1; return 0;}bool delete2(int a,int b,int c){ if((s[c]-s[b])*(b-a)<(s[b]-s[a])*(c-b)) return 1; return 0;}int main(){ while(~scanf("%d%d",&n,&k)) { for(int i=1;i<=n;i++) scanf("%lf",&a[i]); for(int i=1;i<=n;i++) s[i]=s[i-1]+a[i]; f1=0; f2=0; q[f2]=0; double ans=0; for(int i=k;i<=n;i++) { while(1) { if(f2-f1+1<2) break; if(delete1(q[f1],q[f1+1],i)) f1++; else break; } ans=max(ans,1.0*(s[i]-s[q[f1]])/(i-q[f1])); while(1) { if(f2-f1+1<2) break; if(delete2(q[f2-1],q[f2],i)) f2--; else break; } f2++; q[f2]=i-k+1; } printf("%d\n",(int)(1000*ans)); } return 0;}
POJ 2018 Best Cow Fences
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。