Swift 学习笔记(面向协议编程)

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Swift 学习笔记(面向协议编程)

2024-09-05 05:13:05 219人阅读

在Swift中协议不仅可以定义方法和属性，而且协议是可以扩展的，最关键的是，在协议的扩展中可以添加一些方法的默认实现，就是在协议的方法中可以实现一些逻辑，由于这个特性，Swift是可以面向协议进行编程的。

扩展协议和默认实现

protocol Record {
    var wins: Int{get}
    var losses:Int{get}
    func winningPercent() -> Double
}

struct BasketballRecord:Record,CustomStringConvertible {
    var wins: Int
    var losses: Int
    
    func winningPercent() -> Double {
        return Double(wins)/Double(wins + losses)
    }
    var description: String {
        return String.init(format: "WINS: %d, LOSSES: %d", [wins,losses])
    }
}

struct baseballRecord:Record,CustomStringConvertible {
    var wins: Int
    var losses: Int
    
    func winningPercent() -> Double {
        return Double(wins)/Double(wins + losses)
    }
    var description: String {
        return String.init(format: "WINS: %d, LOSSES: %d", [wins,losses])
    }
}

let teamRecord = BasketballRecord(wins: 2, losses: 10)
print(teamRecord)

let baseball = baseballRecord(wins: 3, losses: 10)
print(baseball)

我们可以看到这两个结构体都分别继承了Record 和 CustomStringConvertible协议其中第一个是我们自定义的协议第二个是系统协议，在Swift中协议也是可以继承的，于是我们可以改写成下面的模式。

protocol Record:CustomStringConvertible {
    var wins: Int{get}
    var losses:Int{get}
    func winningPercent() -> Double
}

struct BasketballRecord:Record {
    var wins: Int
    var losses: Int
    
    func winningPercent() -> Double {
        return Double(wins)/Double(wins + losses)
    }
    var description: String {
        return String.init(format: "WINS: %d, LOSSES: %d", [wins,losses])
    }
}

struct baseballRecord:Record {
    var wins: Int
    var losses: Int
    
    func winningPercent() -> Double {
        return Double(wins)/Double(wins + losses)
    }
    var description: String {
        return String.init(format: "WINS: %d, LOSSES: %d", [wins,losses])
    }
}

你会看到还是有冗余的代码就是遵守CustomStringConvertible协议实现的description的返回时一样的，这个时候我们就像进一步封装，那么我们该怎么做呢？这个其实就用到我们所说：协议是可以扩展的，而且在扩展中协议的属性和方法是可以有默认实现的，我们可以这样写：

protocol Record:CustomStringConvertible {
    var wins: Int{get}
    var losses:Int{get}
    func winningPercent() -> Double
}

//扩展协议
extension Record {
    
    var description: String {
        return String.init(format: "WINS: %d, LOSSES: %d", [wins,losses])
    }
}

struct BasketballRecord:Record {
    var wins: Int
    var losses: Int
    
    func winningPercent() -> Double {
        return Double(wins)/Double(wins + losses)
    }
    
}

struct baseballRecord:Record {
    var wins: Int
    var losses: Int
    
    func winningPercent() -> Double {
        return Double(wins)/Double(wins + losses)
    }
}

这样写是不是就方便多了呢，但是仔细观察我们在遵守协议的各个结构体中是不是还有逻辑类似，但是写了好几遍的代码呢，我们是不是也可以考虑，将计算胜率的方法也迁移到扩展中呢？

protocol Record:CustomStringConvertible {
    var wins: Int {get}
    var losses:Int {get}
    
}

//扩展协议
extension Record {
    
    var description: String {
        return String.init(format: "wins: %d, losses:%d", [wins,losses])
    }
    
    var gamePlayed:Int {
        return wins + losses
    }
    
    func winningPercent() -> Double {
        return Double(wins)/Double(gamePlayed)
    }
    
}

struct BasketballRecord:Record {
    var wins: Int
    var losses: Int
}

struct baseballRecord:Record {
    var wins: Int
    var losses: Int
}

是不是更加简便了呢，那么假如一场比赛既有输赢，又有打平的时候呢，我们新增加一个协议，当遵守了不同的协议，他们执行的默认方法，就是既满足了有输赢又可以打平里面扩展的方法的默认实现，如果只遵守了一个Record协议，则执行扩展Record中的默认实现。

protocol Record:CustomStringConvertible {
    var wins: Int {get}
    var losses:Int {get}
    
}

//打平的协议
protocol Tieable {
    var ties:Int {get set}
}
//扩展即遵守了Record协议的又遵守了Tieable协议
extension Record where Self:Tieable {
    var gamePlayed:Int {
        return wins + losses + ties
    }
    func winningPercent() -> Double {
        return Double(wins)/Double(gamePlayed)
    }

}
//扩展协议
extension Record {
    
    var description: String {
        return String.init(format: "wins: %d, losses:%d", [wins,losses])
    }
    
    var gamePlayed:Int {
        return wins + losses
    }
    
    func winningPercent() -> Double {
        return Double(wins)/Double(gamePlayed)
    }
    
}

struct BasketballRecord:Record {
    var wins: Int
    var losses: Int
}

struct baseballRecord:Record {
    var wins: Int
    var losses: Int
}
//可以平局的
struct FootBallRecord:Record,Tieable {
    var wins: Int
    var losses: Int
    var ties: Int
}

协议聚合

语法结构

协议1 & 协议2

示例代码

//判断是否可以获得奖励的协议
protocol Prizable {
    func isPrizable() -> Bool
}

func award(prizable: Prizable & CustomStringConvertible){
    if prizable.isPrizable() {
        print(prizable)
        print("你可以获奖")
    }else{
        print("您不可以获奖")
    }
}

表示这个函数的参数即遵守Prizable协议，也遵守了CustomStringConvertible的协议。

泛型约束

struct Student:CustomStringConvertible,Equatable,Comparable,Prizable{
    var name:String
    var score:Int
    var description: String {
        return name
    }
    func isPrizable() -> Bool {
        return score > 60
    }
}

func == (s1:Student,s2:Student)->Bool {
    return s1.score == s2.score
}
func < (s1:Student,s2:Student) ->Bool {
    return s1.score < s2.score
}

let tian = Student(name: "tian", score: 90)
let a = Student(name: "Alice", score: 80)
let b = Student(name: "Bob", score: 67)
let c = Student(name: "Karl", score: 66)

let students = [a,b,c,tian]
//报错 原因是因为Comparable 这个协议的实现中自己调用了自己 此时这种协议不能当作一种类型 在这种情况下我们可以改为下面的代码
func topOne(seq:[Comparable]) ->Comparable { 
    
}

为了解决上面的错误，我们可以这样写

struct Student:CustomStringConvertible,Equatable,Comparable,Prizable{
    var name:String
    var score:Int
    var description: String {
        return name
    }
    func isPrizable() -> Bool {
        return score > 60
    }
}

func == (s1:Student,s2:Student)->Bool {
    return s1.score == s2.score
}
func < (s1:Student,s2:Student) ->Bool {
    return s1.score < s2.score
}

let tian = Student(name: "tian", score: 90)
let a = Student(name: "Alice", score: 80)
let b = Student(name: "Bob", score: 67)
let c = Student(name: "Karl", score: 66)

let students = [a,b,c,tian]

func topOne<T:Comparable>(seq:[T]) ->T  {
    assert(seq.count > 0)
    return seq.reduce(seq[0]){
        max($0, $1)
    }
}
topOne(seq: [4,5,7,8])

func topPrizableOne<T:Comparable & Prizable>(seq:[T]) ->T? {
    return seq.reduce(nil) {
        (tempTop:T?,contender:T) in
        guard contender.isPrizable() else {
            return tempTop
        }
        guard let tempTop = tempTop else {
            return contender
        }
        
        return max(tempTop, contender)
    }
}
topPrizableOne(seq: students)?.name

Swift 学习笔记(面向协议编程)

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