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UVA 11400 Lighting System Design DP

最优情况不可能跨过一种灯泡,为什么? 因为如果A换成C是划算的那么如果A换成B是不划算的那么可以将A和B都换成C,肯定是划算的= =

然后就是简单DP了。

#include <cstdio>#include <cstring>#include <iostream>#include <map>#include <set>#include <vector>#include <string>#include <queue>#include <deque>#include <bitset>#include <list>#include <cstdlib>#include <climits>#include <cmath>#include <ctime>#include <algorithm>#include <stack>#include <sstream>#include <numeric>#include <fstream>#include <functional>using namespace std;#define MP make_pair#define PB push_backtypedef long long LL;typedef unsigned long long ULL;typedef vector<int> VI;typedef pair<int,int> pii;const int INF = INT_MAX / 3;const double eps = 1e-8;const LL LINF = 1e17;const double DINF = 1e60;const int maxn = 1005;struct Lamp {    int v,k,c,l;    Lamp(int v=0,int k=0,int c=0,int l=0):v(v),k(k),c(c),l(l) {}    bool operator < (const Lamp &x) const {        return v < x.v;    }};Lamp lamp[maxn];int n, cost[maxn], cnt[maxn];int main() {    while(scanf("%d",&n), n) {        for(int i = 1;i <= n;i++) {            int v,k,c,l; scanf("%d%d%d%d",&v,&k,&c,&l);            lamp[i] = Lamp(v,k,c,l);        }        sort(lamp + 1, lamp + 1 + n);        for(int i = 1;i <= n;i++) cnt[i] = cnt[i - 1] + lamp[i].l;        for(int i = 1;i <= n;i++) {            cost[i] = INF;            for(int j = i;j >= 1;j--) {                int nowval = cost[j - 1] + (cnt[i] - cnt[j - 1]) * lamp[i].c + lamp[i].k;                cost[i] = min(cost[i],nowval);            }        }        printf("%d\n",cost[n]);    }    return 0;}

  

UVA 11400 Lighting System Design DP