首页 > 代码库 > Codeforces Round #266 (Div. 2) A

Codeforces Round #266 (Div. 2) A

2024-07-22 08:46:28   221人阅读

题目：

A. Cheap Travel
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Ann has recently started commuting by subway. We know that a one ride subway ticket costs a rubles. Besides, Ann found out that she can buy a special ticket for m rides (she can buy it several times). It costs b rubles. Ann did the math; she will need to use subway n times. Help Ann, tell her what is the minimum sum of money she will have to spend to make n rides?

Input

The single line contains four space-separated integers n, m, a, b (1?≤?n,?m,?a,?b?≤?1000) — the number of rides Ann has planned, the number of rides covered by the m ride ticket, the price of a one ride ticket and the price of an m ride ticket.

Output

Print a single integer — the minimum sum in rubles that Ann will need to spend.

Sample test(s)
input
6 2 1 2
output
6
input
5 2 2 3
output
8
Note

In the first sample one of the optimal solutions is: each time buy a one ride ticket. There are other optimal solutions. For example, buy three m ride tickets.

题意分析：

很简单的贪心，但是边缘数据和取整注意细节。

代码：

#include <iostream>
#include <string>
#include <cstdio>
#include <cstring>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <cmath>
#include <sstream>
#include <algorithm>
#include <numeric>


using namespace std;


int main()
{
    int n, m, a, b;
    cin >> n >> m >> a >> b;
    double f = (double)b/(double)m;
    if (f < (double)a)
    {
        int k1 = n/m;
        int k2 = n-k1*m;
        int k3 = (k1+1)*b;
        cout << min(k1*b+k2*a, k3);
    }
    else
    {
        cout << n*a << endl;
    }
    return 0;
}


Codeforces Round #266 (Div. 2) A


联系
我们