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保研机试准备之常用机试代码
Java快速IO
static StreamTokenizer sc = new StreamTokenizer(new BufferedReader( new InputStreamReader(System.in))); static PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out)); int n = nextInt(); int m = nextInt(); out.flush(); out.close(); public static int nextInt() throws IOException { sc.nextToken(); return (int) sc.nval; }
并查集
/** * Union Find Set * @author andong * */import java.util.Arrays;public class UFS { final int MAX = 20; int[] par; int[] rank; public UFS(){ par = new int[MAX]; rank = new int[MAX]; for(int i=0;i<MAX;i++){ par[i] = i; } Arrays.fill(rank, 1); } public int find(int x){ int px = x; while(px!=par[px]){ px = par[px]; } int t; while(x!=px){ t = par[x]; par[x] = px; x = t; } return px; } public void union(int x,int y){ int px = find(x); int py = find(y); if(px != py){ if(rank[px]>=rank[py]){ par[py] = px; rank[px]+=rank[py]; } else{ par[px] = py; rank[py]+=rank[px]; } } } public int count(){ int cnt = 0; for(int i=0;i<MAX;i++){ if(par[i]==i) cnt++; } return cnt; }}
拓扑排序
public class Topo { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int[][] g = new int[n+1][n+1]; int m = sc.nextInt(); for(int i=0;i<m;i++){ int a = sc.nextInt(); int b = sc.nextInt(); g[a][b] = 1; } int[] cnt = new int[n+1]; boolean[] in = new boolean[n+1]; Arrays.fill(in, false); Arrays.fill(cnt, 0); for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ if(g[i][j]==1) cnt[j]++; } } Queue<Integer> q = new LinkedList<Integer>(); for(int i=1;i<=n;i++){ if(cnt[i]==0){ q.add(i); in[i] = true; } } while(!q.isEmpty()){ int p = q.remove(); for(int i=1;i<=n;i++){ if(g[p][i]==1){ cnt[i]--; if(cnt[i]==0&&!in[i]){ q.add(i); in[i] = true; } } } System.out.print(p); } }}
最小生成树的Kruskal算法
import java.util.ArrayList;import java.util.Comparator;import java.util.PriorityQueue;/** * Kruskal算法练习 * @author andong * */public class Kruskal { public static final int INF = Integer.MAX_VALUE; public static int nV; public static int[][] graph; public static UFS ufs; public static PriorityQueue<Edge> priq; public static ArrayList<Edge> list; public static void init(int[][] g){ nV = g.length; graph = g; ufs = new UFS(nV); Comparator<Edge> com = new Comparator<Kruskal.Edge>() { @Override public int compare(Edge o1, Edge o2) { return o1.w<o2.w?-1:1; } }; priq = new PriorityQueue<Edge>(nV,com); list = new ArrayList<Edge>(); //i->j的图 for(int i=0;i<nV;i++){ for(int j=0;j<nV;j++){ if(graph[i][j]>0&&graph[i][j]<INF){ priq.add(new Edge(i, j,graph[i][j])); } } } work(); } public static void work(){ int cnt = 0; while(!priq.isEmpty()){ Edge edge = priq.remove(); if(ufs.find(edge.s)!=ufs.find(edge.e)){ ufs.union(edge.s, edge.e); list.add(edge); cnt++; } if(cnt==nV-1){ output(); break; } } } public static void output(){ for(int i=0;i<list.size();i++){ System.out.println(list.get(i).w); } } static class Edge { int s,e,w; public Edge(int s,int e,int w){ this.s = s; this.e = e; this.w = w; } } public static void main(String[] args) { int[][] a = {{0,1,2,4},{0,0,2,5},{0,0,0,3},{0,0,0,0}}; Kruskal.init(a); }}
最短路径的Dijkstra算法
import java.util.ArrayList;import java.util.Comparator;import java.util.PriorityQueue;/** * Dijkstra算法练习 * @author andong * */public class Dijkstra { public static int nV; public static int src; public static int[][] graph; public static int[] dist; public static ArrayList<Integer> list; public static PriorityQueue<point> priq; public static void init(int[][] g,int s){ nV = g.length; src = s; graph = g; dist = new int[nV]; list = new ArrayList<Integer>(); Comparator<point> com = new Comparator<point>() { public int compare(point o1, point o2) { return o1.dist<o2.dist?-1:1; } }; priq = new PriorityQueue<point>(nV,com); for(int i=0;i<nV;i++){ dist[i] = graph[src][i]; if(i!=src) priq.add(new point(i, dist[i])); } } public static void work(){ while(!priq.isEmpty()){ point p = priq.remove(); for(int i=0;i<nV;i++){ int tmp = dist[p.pos]+graph[p.pos][i]; if(tmp<dist[i]){ dist[i] = tmp; priq.add(new point(i, dist[i])); } } list.add(p.pos); } } public static void output(int dest){ System.out.println(dist[dest]); for(int i=0;i<list.size();i++){ System.out.print(list.get(i)); if(list.get(i)==dest){ System.out.println(); break; } } } static class point{ int pos,dist; public point(int pos,int dist){ this.pos = pos; this.dist = dist; } } public static void main(String[] args) { int[][] a = {{0,1,2,4},{0,0,2,5},{0,0,0,3},{0,0,0,0}}; Dijkstra.init(a, 0); for(int i=0;i<4;i++){ Dijkstra.output(i); } }}
最短路径的Floyd算法
import java.util.Arrays;/** * Floyd算法练习 * @author andong * */public class Floyd { public static int nV; public static int[][] dist; public static int[][] inter; public static void init(int[][] g){ nV = g.length; dist = new int[nV][nV]; for(int i=0;i<nV;i++) for(int j=0;j<nV;j++){ if(g[i][j]<Integer.MAX_VALUE) dist[i][j] = g[i][j]; else dist[i][j] = -1; } inter = new int[nV][nV]; for(int i=0;i<nV;i++){ for(int j=0;j<nV;j++){ inter[i][j] = j; } } work(); } public static void work(){ for(int k=0;k<nV;k++){ for(int i=0;i<nV;i++){ for(int j=0;j<nV;j++){ if(dist[i][k]>0&&dist[k][j]>0&&dist[i][j]>dist[i][k]+dist[k][j]){ dist[i][j] = dist[i][k]+dist[k][j]; inter[i][j] = k; } } } } } public static void outputDist(int src,int dest){ System.out.println(dist[src][dest]); } public static void outputPath(int src,int dest){ if(src=http://www.mamicode.com/=dest){ System.out.print(src); return; } System.out.print(src); outputPath(inter[src][dest], dest); } public static void main(String[] args) { int INF = Integer.MAX_VALUE; int[][] a = {{0,1,2,4},{INF,0,2,7},{INF,INF,0,3},{INF,INF,INF,0}}; Floyd.init(a); for(int i=0;i<4;i++) outputDist(1, i); outputPath(1, 3); }}
由前序序列和中序序列构建树
1)序列用字符串表示
public static void build(String a,String b){ int len = a.length(); if(len==1){ System.out.println(a); } else if(len>1){ char c = a.charAt(0); String[] temp = b.split(c+""); int len0 = temp[0].length(); int len1 = temp[1].length(); build(a.substring(1, 1+len0),temp[0]); build(a.substring(len-len1),temp[1]); System.out.print(c); } }
2)序列用整数数组表示
public static void build(int pos, int[] pre, int[] in) { if (pre.length <= 0) return; tree[pos] = pre[0]; int idx = 0; for (idx = 0; idx < pre.length; idx++) { if (in[idx] == pre[0]) break; } if (idx > 0 && pos * 2 < tree.length) { int[] leftpre = new int[idx]; int[] leftin = new int[idx]; System.arraycopy(pre, 1, leftpre, 0, idx); System.arraycopy(in, 0, leftin, 0, idx); build(pos * 2, leftpre, leftin); } if (idx < pre.length - 1 && pos * 2 + 1 < tree.length - 1) { int[] rightpre = new int[pre.length - idx - 1]; int[] rightin = new int[in.length - idx - 1]; System.arraycopy(pre, 1 + idx, rightpre, 0, pre.length - 1 - idx); System.arraycopy(in, 1 + idx, rightin, 0, in.length - 1 - idx); build(pos * 2 + 1, rightpre, rightin); } }
保研机试准备之常用机试代码
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