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usaco-4.4-shutter-passed

2024-07-23 08:22:15   219人阅读

此题取巧了，Usaco在这题上并没有指明不可以用分析法，而且dfs肯定TLE，所以我们取巧。

先观察样例数据，如果把还没移动的那一步也算上，那么空格的位置为

4 3 5 6 4 2 1 3 5 7 6 4 2 3 5 4 (n=3,样例)

5 4 6 7 5 3 2 4 6 8 9 7 5 3 1 2 4 6 8 7 5 3 4 6 5 (n=4)

我们凭借极其敏锐的眼光发现这组序列为

４35 642 1357 642 35 4 (n=3,样例)

5 46 753 2468 97531 2468 753 46 5 (n=4)

即长度为1,2,3,4,...,n,n+1,n,...,4,3,2,1这样的2n+1组等差序列

我们讨论第1~n+1组序列，这些序列满足

　　*公差的绝对值为2

　　*奇数组为降序列，偶数组为升序列

　　*对于第i组(1<=i<=n+1),若为奇数组则首项为n+i，偶数组则首项为n-i+2

对于第n+2~2n+1组，可以由对称性求出。

输出时从第二组开始即可。

把规律总结成这样后，代码应该很好写了吧。

/*ID: qq104801LANG: C++TASK: shuttle*/#include <iostream>#include <fstream>#include <cstring>#include <vector>#include <queue>#include <stack>#include <algorithm>using namespace std;void test(){       freopen("shuttle.in","r",stdin);      freopen("shuttle.out","w",stdout);      int n,p,s=0,k;    cin>>n;    p=n+1;    for(int i=2;i<=2*n+1;i++)    {        k=(i<=n+1)?i:2*n+2-i;        p+=(k&1)^(i>n+1)?1:-1;        s++;        cout<<p<<((s%20==0||i==2*n+1) ? ‘\n‘ : ‘ ‘);        for(int j=2;j<=k;j++)            p+=(k&1)?-2:2,s++,            cout<<p<<((s%20)?‘ ‘:‘\n‘);    } }int main () {            test();            return 0;}

test data:

USACO TrainingGrader Results     14 users onlineBRA/1 CHN/4 IDN/1 IND/1 KOR/1 PER/1 USA/4 VNM/1USER: cn tom [qq104801]TASK: shuttleLANG: C++Compiling...Compile: OKExecuting...   Test 1: TEST OK [0.008 secs, 3372 KB]   Test 2: TEST OK [0.011 secs, 3372 KB]   Test 3: TEST OK [0.011 secs, 3372 KB]   Test 4: TEST OK [0.008 secs, 3372 KB]   Test 5: TEST OK [0.005 secs, 3372 KB]   Test 6: TEST OK [0.008 secs, 3372 KB]   Test 7: TEST OK [0.008 secs, 3372 KB]   Test 8: TEST OK [0.011 secs, 3372 KB]   Test 9: TEST OK [0.008 secs, 3372 KB]   Test 10: TEST OK [0.016 secs, 3372 KB]All tests OK.YOUR PROGRAM (‘shuttle‘) WORKED FIRST TIME! That‘s fantastic -- and a rare thing. Please accept these special automated congratulations.Here are the test data inputs:------- test 1 ----1------- test 2 ----3------- test 3 ----4------- test 4 ----5------- test 5 ----7------- test 6 ----8------- test 7 ----9------- test 8 ----10------- test 9 ----11------- test 10 ----12Keep up the good work!Thanks for your submission!

 

usaco-4.4-shutter-passed


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