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poj1002-487-3279
http://poj.org/problem?id=1002
487-3279
| Time Limit: 2000MS | Memory Limit: 65536K | |
| Total Submissions: 288073 | Accepted: 51697 |
Description
Businesses like to have memorable telephone numbers. One way to make a telephone number memorable is to have it spell a memorable word or phrase. For example, you can call the University of Waterloo by dialing the memorable TUT-GLOP. Sometimes only part of the number is used to spell a word. When you get back to your hotel tonight you can order a pizza from Gino‘s by dialing 310-GINO. Another way to make a telephone number memorable is to group the digits in a memorable way. You could order your pizza from Pizza Hut by calling their ``three tens‘‘ number 3-10-10-10.
The standard form of a telephone number is seven decimal digits with a hyphen between the third and fourth digits (e.g. 888-1200). The keypad of a phone supplies the mapping of letters to numbers, as follows:
A, B, and C map to 2
D, E, and F map to 3
G, H, and I map to 4
J, K, and L map to 5
M, N, and O map to 6
P, R, and S map to 7
T, U, and V map to 8
W, X, and Y map to 9
There is no mapping for Q or Z. Hyphens are not dialed, and can be added and removed as necessary. The standard form of TUT-GLOP is 888-4567, the standard form of 310-GINO is 310-4466, and the standard form of 3-10-10-10 is 310-1010.
Two telephone numbers are equivalent if they have the same standard form. (They dial the same number.)
Your company is compiling a directory of telephone numbers from local businesses. As part of the quality control process you want to check that no two (or more) businesses in the directory have the same telephone number.
The standard form of a telephone number is seven decimal digits with a hyphen between the third and fourth digits (e.g. 888-1200). The keypad of a phone supplies the mapping of letters to numbers, as follows:
A, B, and C map to 2
D, E, and F map to 3
G, H, and I map to 4
J, K, and L map to 5
M, N, and O map to 6
P, R, and S map to 7
T, U, and V map to 8
W, X, and Y map to 9
There is no mapping for Q or Z. Hyphens are not dialed, and can be added and removed as necessary. The standard form of TUT-GLOP is 888-4567, the standard form of 310-GINO is 310-4466, and the standard form of 3-10-10-10 is 310-1010.
Two telephone numbers are equivalent if they have the same standard form. (They dial the same number.)
Your company is compiling a directory of telephone numbers from local businesses. As part of the quality control process you want to check that no two (or more) businesses in the directory have the same telephone number.
Input
The input will consist of one case. The first line of the input specifies the number of telephone numbers in the directory (up to 100,000) as a positive integer alone on the line. The remaining lines list the telephone numbers in the directory, with each number alone on a line. Each telephone number consists of a string composed of decimal digits, uppercase letters (excluding Q and Z) and hyphens. Exactly seven of the characters in the string will be digits or letters.
Output
Generate a line of output for each telephone number that appears more than once in any form. The line should give the telephone number in standard form, followed by a space, followed by the number of times the telephone number appears in the directory. Arrange the output lines by telephone number in ascending lexicographical order. If there are no duplicates in the input print the line:
No duplicates.
No duplicates.
Sample Input
124873279ITS-EASY888-45673-10-10-10888-GLOPTUT-GLOP967-11-11310-GINOF101010888-1200-4-8-7-3-2-7-9-487-3279
Sample Output
310-1010 2487-3279 4888-4567 3
注意：如果算法里采用转化成整数比较比对，注意最后输出时，数字长度可能小于7的情况。
代码：
1 #include <cstdio> 2 #include <map> 3 4 int StrToNum (const char *t, int len); 5 6 int main () 7 { 8 int count, tmp32; 9 scanf("%d", &count); 10 getchar(); 11 12 std::map<int, int> stlm; 13 std::map<int, int>::iterator it; 14 15 char c[20]; 16 int clen; 17 18 for (int i = 0; i < count; i++) 19 { 20 for (clen = 0; ; clen++) 21 { 22 while (scanf("%c", &c[clen]), c[clen] == ‘-‘) 23 { 24 } 25 26 if (c[clen] == ‘\n‘) 27 { 28 break; 29 } 30 } 31 32 tmp32 = StrToNum(c, clen); 33 it = stlm.find(tmp32); 34 if (it == stlm.end()) 35 { 36 stlm[tmp32] = 1; 37 } 38 else 39 { 40 stlm[tmp32]++; 41 } 42 } 43 44 bool bret = false; 45 for (it = stlm.begin(); it != stlm.end(); it++) 46 { 47 if (it->second > 1) 48 { 49 bret = true; 50 printf("%03d-%04d %d\n", (it->first) / 10000, (it->first) % 10000, it->second); 51 } 52 } 53 54 if (!bret) 55 { 56 puts("No duplicates."); 57 } 58 59 return 0; 60 } 61 62 int StrToNum (const char *t, int len) 63 { 64 int j = 0, v = 0; 65 66 for (int i = 0; ; i++) 67 { 68 switch (t[i]) 69 { 70 case ‘A‘: 71 v += 2; 72 break; 73 case ‘B‘: 74 v += 2; 75 break; 76 case ‘C‘: 77 v += 2; 78 break; 79 case ‘D‘: 80 v += 3; 81 break; 82 case ‘E‘: 83 v += 3; 84 break; 85 case ‘F‘: 86 v += 3; 87 break; 88 case ‘G‘: 89 v += 4; 90 break; 91 case ‘H‘: 92 v += 4; 93 break; 94 case ‘I‘: 95 v += 4; 96 break; 97 case ‘J‘: 98 v += 5; 99 break;100 case ‘K‘:101 v += 5;102 break;103 case ‘L‘:104 v += 5;105 break;106 case ‘M‘:107 v += 6;108 break;109 case ‘N‘:110 v += 6;111 break;112 case ‘O‘:113 v += 6;114 break;115 case ‘P‘:116 v += 7;117 break;118 case ‘R‘:119 v += 7;120 break;121 case ‘S‘:122 v += 7;123 break;124 case ‘T‘:125 v += 8;126 break;127 case ‘U‘:128 v += 8;129 break;130 case ‘V‘:131 v += 8;132 break;133 case ‘W‘:134 v += 9;135 break;136 case ‘X‘:137 v += 9;138 break;139 case ‘Y‘:140 v += 9;141 break;142 default:143 v += t[i] - ‘0‘;144 }145 146 if (i + 1 < len)147 {148 v *= 10;149 }150 else151 {152 break;153 }154 }155 156 return v;157 }
poj1002-487-3279
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