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POJ 3279 Fliptile
Time Limit: 2000MS | Memory Limit: 65536K | |
Total Submissions: 8322 | Accepted: 3102 |
Description
Farmer John knows that an intellectually satisfied cow is a happy cow who will give more milk. He has arranged a brainy activity for cows in which they manipulate an M × N grid (1 ≤ M ≤ 15; 1 ≤ N ≤ 15) of square tiles, each of which is colored black on one side and white on the other side.
As one would guess, when a single white tile is flipped, it changes to black; when a single black tile is flipped, it changes to white. The cows are rewarded when they flip the tiles so that each tile has the white side face up. However, the cows have rather large hooves and when they try to flip a certain tile, they also flip all the adjacent tiles (tiles that share a full edge with the flipped tile). Since the flips are tiring, the cows want to minimize the number of flips they have to make.
Help the cows determine the minimum number of flips required, and the locations to flip to achieve that minimum. If there are multiple ways to achieve the task with the minimum amount of flips, return the one with the least lexicographical ordering in the output when considered as a string. If the task is impossible, print one line with the word "IMPOSSIBLE".
Input
Lines 2..M+1: Line i+1 describes the colors (left to right) of row i of the grid with N space-separated integers which are 1 for black and 0 for white
Output
Sample Input
4 4 1 0 0 1 0 1 1 0 0 1 1 0 1 0 0 1
Sample Output
0 0 0 0 1 0 0 1 1 0 0 1 0 0 0 0
//????现在还不会做,慢慢看吧,在网上看了一下他们的解题报告
1.如果处理了前面n-1行了,我们只要判断最后一行是否是全为0
2.现在才明白怎们用暴力方法,每一个格子都有两种操作 翻还是不翻,这样就有2^(M+N)种可能性,然后一次枚举每一种,找出翻转最少的就是它的解。
3.还是不知道怎么弄,以后持续更新吧。
POJ 3279 Fliptile