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C puzzles详解【46-50题】

2024-07-24 01:26:54   219人阅读

第四十六题

What does the following macro do?   #define ROUNDUP(x,n) ((x+n-1)&(~(n-1)))
题目讲解：
参考：http://bbs.chinaunix.net/forum.php?mod=viewthread&tid=814501
用于内存对齐，n为2的幂。

第四十七题

Most of the C programming books, give the following example for the definition of macros.   #define isupper(c) (((c) >= ‘A‘) && ((c) <= ‘Z‘))But there would be a serious problem with the above definition of macro, if it is used as follows (what is the problem??)   char c;  /* ... */  if(isupper(c++))  {      /* ... */  }But most of the libraries implement the isupper (declared in ctypes.h) as a macro (without any side effects). Find out how isupper() is implemented on your system.
知识点讲解：
Linux内核中isupper的实现见lib/ctype.c和include/linux/ctype.h。
ctype.h代码如下：
#ifndef _LINUX_CTYPE_H#define _LINUX_CTYPE_H/* * NOTE! This ctype does not handle EOF like the standard C * library is required to. */#define _U    0x01    /* upper */#define _L    0x02    /* lower */#define _D    0x04    /* digit */#define _C    0x08    /* cntrl */#define _P    0x10    /* punct */#define _S    0x20    /* white space (space/lf/tab) */#define _X    0x40    /* hex digit */#define _SP    0x80    /* hard space (0x20) */extern const unsigned char _ctype[];#define __ismask(x) (_ctype[(int)(unsigned char)(x)])#define isalnum(c)    ((__ismask(c)&(_U|_L|_D)) != 0)#define isalpha(c)    ((__ismask(c)&(_U|_L)) != 0)#define iscntrl(c)    ((__ismask(c)&(_C)) != 0)#define isdigit(c)    ((__ismask(c)&(_D)) != 0)#define isgraph(c)    ((__ismask(c)&(_P|_U|_L|_D)) != 0)#define islower(c)    ((__ismask(c)&(_L)) != 0)#define isprint(c)    ((__ismask(c)&(_P|_U|_L|_D|_SP)) != 0)#define ispunct(c)    ((__ismask(c)&(_P)) != 0)/* Note: isspace() must return false for %NUL-terminator */#define isspace(c)    ((__ismask(c)&(_S)) != 0)#define isupper(c)    ((__ismask(c)&(_U)) != 0)#define isxdigit(c)    ((__ismask(c)&(_D|_X)) != 0)#define isascii(c) (((unsigned char)(c))<=0x7f)#define toascii(c) (((unsigned char)(c))&0x7f)static inline unsigned char __tolower(unsigned char c){    if (isupper(c))        c -= ‘A‘-‘a‘;    return c;}static inline unsigned char __toupper(unsigned char c){    if (islower(c))        c -= ‘a‘-‘A‘;    return c;}#define tolower(c) __tolower(c)#define toupper(c) __toupper(c)#endif
ctype.c代码如下：
/* *  linux/lib/ctype.c * *  Copyright (C) 1991, 1992  Linus Torvalds */#include <linux/ctype.h>#include <linux/module.h>const unsigned char _ctype[] = {_C,_C,_C,_C,_C,_C,_C,_C,                /* 0-7 */_C,_C|_S,_C|_S,_C|_S,_C|_S,_C|_S,_C,_C,            /* 8-15 */_C,_C,_C,_C,_C,_C,_C,_C,                /* 16-23 */_C,_C,_C,_C,_C,_C,_C,_C,                /* 24-31 */_S|_SP,_P,_P,_P,_P,_P,_P,_P,                /* 32-39 */_P,_P,_P,_P,_P,_P,_P,_P,                /* 40-47 */_D,_D,_D,_D,_D,_D,_D,_D,                /* 48-55 */_D,_D,_P,_P,_P,_P,_P,_P,                /* 56-63 */_P,_U|_X,_U|_X,_U|_X,_U|_X,_U|_X,_U|_X,_U,        /* 64-71 */_U,_U,_U,_U,_U,_U,_U,_U,                /* 72-79 */_U,_U,_U,_U,_U,_U,_U,_U,                /* 80-87 */_U,_U,_U,_P,_P,_P,_P,_P,                /* 88-95 */_P,_L|_X,_L|_X,_L|_X,_L|_X,_L|_X,_L|_X,_L,        /* 96-103 */_L,_L,_L,_L,_L,_L,_L,_L,                /* 104-111 */_L,_L,_L,_L,_L,_L,_L,_L,                /* 112-119 */_L,_L,_L,_P,_P,_P,_P,_C,                /* 120-127 */0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,            /* 128-143 */0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,            /* 144-159 */_S|_SP,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,    /* 160-175 */_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,_P,    /* 176-191 */_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,_U,    /* 192-207 */_U,_U,_U,_U,_U,_U,_U,_P,_U,_U,_U,_U,_U,_U,_U,_L,    /* 208-223 */_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,_L,    /* 224-239 */_L,_L,_L,_L,_L,_L,_L,_P,_L,_L,_L,_L,_L,_L,_L,_L};    /* 240-255 */EXPORT_SYMBOL(_ctype);
_ctype数组中的每个元素的值对应ASCII码为0-255的每个字符的类型，以字符的ASCII码为索引即可获取到相应字符的类型。

第四十八题

I hope you know that ellipsis (...) is used to specify variable number of arguments to a function. (What is the function prototype declaration for printf?) What is wrong with the following delcaration?   int VarArguments(...)  {      /*....*/      return 0;  }
知识点讲解：
对于带有不定参数的函数，用va_start，va_arg，va_end对参数进行索引，内核代码中va_*系列函数的实现在
include/acpi/platform/acenv.h中

#ifndef va_arg#ifndef _VALIST#define _VALISTtypedef char *va_list;#endif                /* _VALIST *//* * Storage alignment properties */#define  _AUPBND                (sizeof (acpi_native_int) - 1)#define  _ADNBND                (sizeof (acpi_native_int) - 1)/* * Variable argument list macro definitions */#define _bnd(X, bnd)            (((sizeof (X)) + (bnd)) & (~(bnd)))#define va_arg(ap, T)           (*(T *)(((ap) += (_bnd (T, _AUPBND))) - (_bnd (T,_ADNBND))))#define va_end(ap)              (void) 0#define va_start(ap, A)         (void) ((ap) = (((char *) &(A)) + (_bnd (A,_AUPBND))))#endif                /* va_arg */
由如上定义可知，va_start返回第一个不定参数的地址，va_arg返回下一个不定参数的地址，va_end用来销毁ap。
va_start和va_end总是成对使用。
va_start获取第一个不定参数的地址时，必须知道最后一个固定参数A的地址，即函数必须提供至少一个固定参数。
故定义形如VarArguments(...)的函数是不正确的。

第四十九题

Write a C program to find the smallest of three integers, without using any of the comparision operators.
题目讲解：
参考：
http://www.geeksforgeeks.org/smallest-of-three-integers-without-comparison-operators/
方法一：
int smallest(int x, int y, int z){  int c = 0;  while ( x && y && z )  {      x--;  y--; z--; c++;  }  return c;}
方法二：
#define CHAR_BIT 8/*Function to find minimum of x and y*/int min(int x, int y){  return  y + ((x - y) & ((x - y) >>            (sizeof(int) * CHAR_BIT - 1)));}/* Function to find minimum of 3 numbers x, y and z*/int smallest(int x, int y, int z){    return min(x, min(y, z));}
方法三：
// Using division operator to find minimum of three numbersint smallest(int x, int y, int z){    if (!(y/x))  // Same as "if (y < x)"        return (!(y/z))? y : z;    return (!(x/z))? x : z;}

 

第五十题

What does the format specifier %n of printf function do?
参考：
http://www.geeksforgeeks.org/g-fact-31/
如：
printf("geeks for %ngeeks ", &c);
将%n之前的字符数赋值给c。

C puzzles详解【46-50题】


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