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leetcode-Maximum Product Subarray zz

LinkedIn 高频题 – Maximum Sum/Product Subarray 

Maximum Sum Subarray是leetcode原题,跟Gas Station的想法几乎一模一样。解答中用到的结论需要用数学简单地证明一下。

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public int maxSubArray(int[] A) {
    int sum = 0;
    int max = Integer.MIN_VALUE;
    for (int i = 0; i < A.length; i++) {
        sum += A[i];
        if (sum > max)
            max = sum;
        if (sum < 0)
            sum = 0;
    }
    return max;
}

Maximum Product Subarray其实只需要不断地记录两个值,max和min。max是到当前为止最大的正product,min是到当前为止最小的负product,或者1。

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public int maxProduct(int[] A) {
    int x = 1;
    int max = 1;
    int min = 1;
    for (int i = 0; i < A.length; i++) {
        if (A[i] == 0) {
            max = 1;
            min = 1;
        } else if (A[i] > 0) {
            max = max * A[i];
            min = Math.min(min * A[i], 1);
        } else {
            int temp = max;
            max = Math.max(min * A[i], 1);
            min = temp * A[i];
        }
        if (max > x)
            x = max;
    }
    return x;
}

 

http://shepherdyuan.wordpress.com/2014/07/23/linkedin-maximum-sumproduct-subarray/

leetcode-Maximum Product Subarray zz