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cookbook 11.1 在文本控制台中显示进度条

任务:

在进行长时间操作时,向用户显示一个"进度指示条"。

解决方案:

#coding=utf-8import sysclass progressbar(object):    def __init__(self,finalcount,block_char=.):        self.finalcount = finalcount        self.blockcount = 0        self.block = block_char        self.f = sys.stdout        if not self.finalcount: return        self.f.write(\n-------- % Process ------- 1\n)        self.f.write(  1  2  3  4  5  6  7  8  9  0\n)        self.f.write(  0  0  0  0  0  0  0  0  0  0\n)    def progress(self,count):        count = min(count,self.finalcount)        if self.finalcount:            percentcomplent = int(round(100.0*count/self.finalcount))            if percentcomplent < 1: percentcomplent = 1        else:            percentcomplent = 100        blockcount = int(percentcomplent//2)#//就是除法,但不四舍五入        if blockcount <= self.blockcount:            return        for i in range(self.blockcount,blockcount):            self.f.write(self.block)        self.f.flush()        self.blockcount = blockcount        if percentcomplent == 100:            self.f.write("\n")        #testif __name__ == __main__:    from time import sleep    pb = progressbar(8,"*")    for count in range(1,9):        pb.progress(count)        sleep(0.2)    pb = progressbar(100)    pb.progress(20)    sleep(0.3)    pb.progress(47)    sleep(0.3)    pb.progress(90)    sleep(0.3)    pb.progress(100)    print "testing 1:"    pb = progressbar(1)    pb.progress(1)        

 

cookbook 11.1 在文本控制台中显示进度条