POJ 3667 Hotel

题目链接

题意：有n个房间，现在有两个操作
1、找到连续长度a的空房间，入住，要尽量靠左边，如果有输出最左边的房间标号，如果没有输出0
2、清空[a, a + b - 1]的房间

思路：线段树的区间合并，记录下左边连续最长和右边连续最长空房间，和每一段的最大值，这样pushup的时候就是进行区间合并，注意查询的时候由于是要尽量左，所以先查左孩子，在查横跨左右的，在查右孩子

代码：

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;

#define lson(x) ((x<<1)+1)
#define rson(x) ((x<<1)+2)

const int N = 50005;

int n, m;

struct Node {
	int l, r, lsum, rsum, sum, sumv, lazy;
	int size() {return r - l + 1;}
	void gao(int v) {
		lazy = v;
		if (v) lsum = rsum = sum = 0;
		else lsum = rsum = sum = r - l + 1;
		sumv = l;
	}
} node[N * 4];

void pushup(int x) {
	if (node[lson(x)].lsum == node[lson(x)].size()) node[x].lsum = node[lson(x)].lsum + node[rson(x)].lsum;
	else node[x].lsum = node[lson(x)].lsum;
	if (node[rson(x)].rsum == node[rson(x)].size()) node[x].rsum = node[lson(x)].rsum + node[rson(x)].rsum;
	else node[x].rsum = node[rson(x)].rsum;
	node[x].sum = node[lson(x)].sum;
	node[x].sumv = node[lson(x)].sumv;
	if (node[x].sum < node[lson(x)].rsum + node[rson(x)].lsum) {
		node[x].sum = node[lson(x)].rsum + node[rson(x)].lsum;
		node[x].sumv = node[lson(x)].r - node[lson(x)].rsum + 1;
	}
	if (node[x].sum < node[rson(x)].sum) {
		node[x].sum = node[rson(x)].sum;
		node[x].sumv = node[rson(x)].sumv;
	}
}

void pushdown(int x) {
	if (node[x].lazy != -1) {
		node[lson(x)].gao(node[x].lazy);
		node[rson(x)].gao(node[x].lazy);
		node[x].lazy = -1;
	}
}

void build(int l, int r, int x = 0) {
	node[x].l = l; node[x].r = r; node[x].lazy = -1;
	if (l == r) {
		node[x].lsum = node[x].rsum = node[x].sum = 1;
		return;
	}
	int mid = (l + r) / 2;
	build(l, mid, lson(x));
	build(mid + 1, r, rson(x));
	pushup(x);
}

void add(int l, int r, int v, int x = 0) {
	if (node[x].l >= l && node[x].r <= r) {
		node[x].gao(v);
		return;
	}
	int mid = (node[x].l + node[x].r) / 2;
	pushdown(x);
	if (l <= mid) add(l, r, v, lson(x));
	if (r > mid) add(l, r, v, rson(x));
	pushup(x);
}

int query(int v, int x = 0) {
	if (node[x].l == node[x].r) {
		if (node[x].sum >= v) return node[x].sumv;
		return 0;
	}
	pushdown(x);
	int ans = 0;
	if (node[lson(x)].sum >= v)
		ans = query(v, lson(x));
	else if (node[lson(x)].rsum + node[rson(x)].lsum >= v) ans = node[lson(x)].r - node[lson(x)].rsum + 1;
	else if (node[rson(x)].sum >= v)
		ans = query(v, rson(x));
	pushup(x);
	return ans;
}

int main() {
	while (~scanf("%d%d", &n, &m)) {
		build(1, n);
		int op, a, b;
		while (m--) {
			scanf("%d%d", &op, &a);
			if (op == 2) {
				scanf("%d", &b);
				add(a, a + b - 1, 0);
			} else {
				int tmp = query(a);
				printf("%d\n", tmp);
				if (tmp == 0) continue;
				add(tmp, tmp + a - 1, 1);
			}
		}
	}
	return 0;
}

POJ 3667 Hotel（线段树）