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HDU-1025 Constructing Roads In JGShining's Kingdom O(nlogn)的最长上升子序列
模板题,唯一问题是当长度为1是,road是单数,不然road是复数roads。
#include <iostream> #include <cstdio> #include <cmath> #include <cstring> #include <queue> #include <vector> #include <cstdlib> #include <algorithm> using namespace std; const int maxn=1021000; struct node { int r; int b; int k; }a[maxn]; int n; int len; int visit[maxn]; int dp[maxn]; bool cmp(node a,node b) { if(a.r==b.r) { return a.b>b.b; } return a.r<b.r; } int find(int i) { int low,high,mid; low=1; high=len; while(low<=high) { int mid=(low+high)/2; if(a[i].b==dp[mid]) { return mid; } if(a[i].b<dp[mid]) { high=mid-1; } else { low=mid+1; } } return low; } int main() { int cas=1; while(scanf("%d",&n)!=EOF) { memset(visit,0,sizeof(visit)); for(int i=1;i<=n;i++) { scanf("%d%d",&a[i].r,&a[i].b); a[i].k=i; } sort(a+1,a+n+1,cmp); dp[1]=a[1].b; visit[1]=1; len=1; for(int i=2;i<=n;i++) { if(a[i].b>dp[len]) { dp[++len]=a[i].b; visit[i]=len; } else { int pos=find(i); dp[pos]=a[i].b; visit[i]=pos; } } printf("Case %d:\n",cas++); if(len==1) { printf("My king, at most %d road can be built.\n\n",len); } else { printf("My king, at most %d roads can be built.\n\n",len); } } return 0; }
HDU-1025 Constructing Roads In JGShining's Kingdom O(nlogn)的最长上升子序列
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