linux=[‘钢弹‘,‘小壁虎‘,‘小虎比‘,‘alex‘,‘wupeiqi‘,‘yuanhao‘]
python=[‘dragon‘,‘钢弹‘,‘zhejiangF4‘,‘小虎比‘]
list=[i for i in linux if i in python]#得出既报名linux又报名python的学生列表
print(list)
list1=[i for i in linux if i not in python]#得出只报名linux，而没有报名python的学生列表
print(list1)
list2=[i for i in python if i not in linux]#得出只报名python，而没有报名linux的学生列表
print(list2)

l=[10,2,3,4,5,6,7]
l1=[int(i)**2 for i in l]#得到一个新列表l1，新列表中每个元素是l中对应每个元素值的平方
print(l1)
l1=[i for i in l1 if i > 40]#过滤出l1中大于40的值，然后求和
print(sum(l1))

shares={
‘IBM‘:36.6,
‘lenovo‘:27.3,
‘huawei‘:40.3,
‘oldboy‘:3.2,
‘ocean‘:20.1
}
# 问题一：得出股票价格大于30的股票名字列表
# 问题二：求出所有股票的总价格
list=[i for i in shares if float(shares[i]) > 30 ]
print(list)
list1=[i for i in shares.values()]
print(sum(list1))