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[WinForm][DevExpress][TreeList]向上递归,获取符合条件的父节点

关键代码:

       /// <summary>        /// 向上递归,获取符合条件的父节点        /// </summary>        /// <param name="node">需要向上递归的节点</param>        /// <param name="conditionHanlder">判断条件【委托】</param>        /// <returns>符合条件的节点【TreeListNode】</returns>        public static TreeListNode GetSelfParentNode(this TreeListNode node, Predicate<TreeListNode> conditionHanlder)        {            TreeListNode _parentNode = node.ParentNode;            TreeListNode _conditonNode = null;            if (_parentNode != null)            {                if (conditionHanlder(_parentNode))//判断上一级父节点是否符合要求                {                    _conditonNode = _parentNode;                }                if (_conditonNode == null)//若没有找到符合要求的节点,递归继续                    _conditonNode = GetSelfParentNode(_parentNode, conditionHanlder);            }            return _conditonNode;        }
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代码使用:

            TreeListNode _node = e.Node;            TreeListNode _condionParent = _node.GetSelfParentNode(n => n.GetNodeType() == NodeType.Cab);//获取类型为CAB类型的父节点            Trace.WriteLine(_condionParent.GetName());
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