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[WinForm][DevExpress][TreeList]节点互斥

关键代码:

        /// <summary>        /// 节点互斥同步        /// 说明        /// eg:        ///TreeListNode _node = e.Node;        ///_node.SyncMutexNodeCheckState(_node.CheckState, n => n.GetNodeType() == NodeType.Cab);        /// </summary>        /// <param name="node">需要互斥同步的节点</param>        /// <param name="checkState">节点状态</param>        /// <param name="checkHanlder">互斥条件【委托】</param>        public static void SyncMutexNodeCheckState(this TreeListNode node, CheckState checkState, Predicate<TreeListNode> checkHanlder)        {            TreeList _tree = node.TreeList;            if (checkHanlder(node))//当前节点符合互斥条件时候            {                _tree.DownRecursiveTree(n => n.CheckState = CheckState.Unchecked);            }            else            {                TreeListNode _curParentNode = node.GetParentNode(checkHanlder);//获取符合互斥条件的父节点                if (_curParentNode == null) return;                TreeListNode _thePubleNode = node.GetPublicParentNode(checkHanlder);//获取符合互斥条件的公共父节点                if (_thePubleNode == null) return;                foreach (TreeListNode n in _thePubleNode.Nodes)                {                    foreach (TreeListNode nc in n.Nodes)                    {                        if (nc != _curParentNode)                        {                            nc.CheckState = CheckState.Unchecked;                            nc.DownRecursiveNode(nr => nr.CheckState = CheckState.Unchecked);                        }                    }                }            }            node.SyncNodeCheckState(checkState);            node.CheckState = checkState;        }    }
        /// <summary>        /// 向上递归,获取符合条件的节点的公共父节点        /// </summary>        /// <param name="node">操作节点</param>        /// <param name="checkHanlder">委托</param>        /// <returns>符合条件的节点</returns>        public static TreeListNode GetPublicParentNode(this TreeListNode node, Predicate<TreeListNode> checkHanlder)        {            TreeListNode _publicPNode = null;            TreeListNode _findNode = node.GetParentNode(checkHanlder);//先获取到条件判断的自身父节点            if (_findNode != null)            {                //开始向上递归                UpwardRecursiveNode(_findNode, n =>                {                    TreeListNode _curpublicNode = n.ParentNode;//获取当前向上递归的父节点                    if (_curpublicNode != null)                    {                        if (_curpublicNode.Nodes.Count > 1)//若有多个子节点,则是公共父节点                        {                            _publicPNode = _curpublicNode;                            return false;//跳出递归                        }                    }                    return true;//继续递归                });            }            return _publicPNode;        }
<style type="text/css">.csharpcode, .csharpcode pre{ font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/}.csharpcode pre { margin: 0em; }.csharpcode .rem { color: #008000; }.csharpcode .kwrd { color: #0000ff; }.csharpcode .str { color: #006080; }.csharpcode .op { color: #0000c0; }.csharpcode .preproc { color: #cc6633; }.csharpcode .asp { background-color: #ffff00; }.csharpcode .html { color: #800000; }.csharpcode .attr { color: #ff0000; }.csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em;}.csharpcode .lnum { color: #606060; }</style>
        /// <summary>        /// 向上递归,获取符合条件的父节点        /// </summary>        /// <param name="node">需要向上递归的节点</param>        /// <param name="conditionHanlder">判断条件【委托】</param>        /// <returns>符合条件的节点【TreeListNode】</returns>        public static TreeListNode GetParentNode(this TreeListNode node, Predicate<TreeListNode> conditionHanlder)        {            TreeListNode _parentNode = node.ParentNode;//获取上一级父节点            TreeListNode _conditonNode = null;            if (_parentNode != null)            {                if (conditionHanlder(_parentNode))//判断上一级父节点是否符合要求                {                    _conditonNode = _parentNode;                }                if (_conditonNode == null)//若没有找到符合要求的节点,递归继续                    _conditonNode = GetParentNode(_parentNode, conditionHanlder);            }            return _conditonNode;        }SyncNodeCheckState代码参考:http://www.cnblogs.com/Yan-Zhiwei/p/3808089.html
说明:
image
如图,Test3和蒙自路Test2都是"cab"类型;
当调用代码如下:
            TreeListNode _node = e.Node;            _node.SyncMutexNodeCheckState(_node.CheckState, n => n.GetNodeType() == NodeType.Cab);

实现的效果就是要么只能勾选“Test3”或者“蒙自路Test2”节点或者子节点,不同同时勾选,应该就是互斥的意思;也是这段代码想实现的效果,希望有所帮助。<style type="text/css">.csharpcode, .csharpcode pre{ font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/}.csharpcode pre { margin: 0em; }.csharpcode .rem { color: #008000; }.csharpcode .kwrd { color: #0000ff; }.csharpcode .str { color: #006080; }.csharpcode .op { color: #0000c0; }.csharpcode .preproc { color: #cc6633; }.csharpcode .asp { background-color: #ffff00; }.csharpcode .html { color: #800000; }.csharpcode .attr { color: #ff0000; }.csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em;}.csharpcode .lnum { color: #606060; }</style>

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