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poj1258(Agri-net)

解题思路:

 

     最小生成树、

 

代码:

 1 #include <algorithm> 2 #include <iostream> 3 #include <sstream> 4 #include <cstdlib> 5 #include <cstring> 6 #include <cstdio> 7 #include <string> 8 #include <bitset> 9 #include <vector>10 #include <queue>11 #include <stack>12 #include <cmath>13 #include <list>14 //#include <map>15 #include <set>16 using namespace std;17 /***************************************/18 #define ll long long19 #define int64 __int6420 /***************************************/21 const int INF = 0x7f7f7f7f;22 const double eps = 1e-8;23 const double PIE=acos(-1.0);24 const int d1x[]= {0,-1,0,1};25 const int d1y[]= {-1,0,1,0};26 const int d2x[]= {0,-1,0,1};27 const int d2y[]= {1,0,-1,0};28 const int fx[]= {-1,-1,-1,0,0,1,1,1};29 const int fy[]= {-1,0,1,-1,1,-1,0,1};30 /***************************************/31 void openfile()32 {33     freopen("data.in","rb",stdin);34     freopen("data.out","wb",stdout);35 }36 /**********************华丽丽的分割线,以上为模板部分*****************/37 #define N 60038 int map[N][N];39 int lowcost[N];40 int vis[N];41 int n;42 int ce;43 int maax;44 int dijstra()45 {46     int i,j,k=0;47     int cnt=0;48     int min;49     for(i=1; i<=n; i++)50     {51         lowcost[i]=map[1][i];52         vis[i]=0;53     }54     vis[1]=1;55     for(i=1; i<n; i++)56     {57         min=INF;58         for(j=1; j<=n; j++)59         {60             if (!vis[j]&&lowcost[j]<min)61             {62                  min=lowcost[j];63                  k=j;64             }65         }66         vis[k]=1;67         cnt+=min;68         for(j=1;j<=n;j++)69             if(!vis[j]&&lowcost[j]>map[k][j])70                 lowcost[j]=map[k][j];71     }72     return cnt;73 }74 int main()75 {76    // int cas;77    // scanf("%d",&cas);78     while(scanf("%d",&n)!=EOF)79     {80         int i,j;81         for(i=0;i<=N;i++)82             for(j=0;j<=N;j++)83                 map[i][j]=INF;84         int x;85         for(i=1;i<=n;i++)86         {87             for(j=1;j<=n;j++)88             {89                 scanf("%d",&x);90                 map[i][j]=x;91             }92         }93         maax=dijstra();94         printf("%d\n",maax);95     }96     return 0;97 }
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