首页 > 代码库 > [leetcode] Path Sum
[leetcode] Path Sum
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and sum = 22
,
5 / 4 8 / / 11 13 4 / \ 7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2
which sum is 22.
https://oj.leetcode.com/problems/path-sum/
思路:递归求解。
注意,val可能是负数。
/** * * be careful: the val might be negtive...*/public class Solution { public boolean hasPathSum(TreeNode root, int sum) { if (root == null) return false; if (sum == root.val && root.left == null && root.right == null) return true; return hasPathSum(root.left, sum - root.val) || hasPathSum(root.right, sum - root.val); } public static void main(String[] args) { TreeNode root = new TreeNode(-5); root.left = new TreeNode(4); root.left.left = new TreeNode(11); root.right = new TreeNode(8); root.right.right = new TreeNode(5); System.out.println(new Solution().hasPathSum(root, 10)); }}
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。