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LeetCode Path Sum
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and sum = 22,
5 / 4 8 / / 11 13 4 / \ 7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */10 public class Solution {11 public boolean hasPathSum(TreeNode root, int sum) {12 if (root == null) {13 return false;14 }15 if (root.val==sum && root.left==null && root.right==null) {16 return true;17 }18 19 return hasPathSum(root.left, sum-root.val) || hasPathSum(root.right, sum-root.val);20 }21 }
LeetCode Path Sum
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