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leetcode--Count and Say
The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ...
1
is read off as "one 1"
or 11
.11
is read off as "two 1s"
or 21
.21
is read off as "one 2
, then one 1"
or 1211
.
Given an integer n, generate the nth sequence.
Note: The sequence of integers will be represented as a string.
?
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 | public class Solution { /**It is simple problem. * @author Averill Zheng * @version 2014-06-07 * @since JDK 1.7 */ public String countAndSay( int n) { String result = "1" ; for ( int i = 1 ; i < n; ++i){ StringBuffer resultBuffer = new StringBuffer(); int length = result.length(); char currentChar = result.charAt( 0 ); int count = 0 ; for ( int j = 0 ; j < length; ++j){ if (currentChar != result.charAt(j)){ resultBuffer.append(count); resultBuffer.append(currentChar - ‘0‘ ); currentChar = result.charAt(j); count = 1 ; } else ++count; } resultBuffer.append(count); resultBuffer.append(currentChar - ‘0‘ ); result = resultBuffer.toString(); } return result; } } |
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