首页 > 代码库 > LeetCode-Read N Characters Given Read4 II - Call multiple times
LeetCode-Read N Characters Given Read4 II - Call multiple times
The API: int read4(char *buf) reads 4 characters at a time from a file.
The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.
By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.
Note:
The read function may be called multiple times.
Solution:
1 /* The read4 API is defined in the parent class Reader4. 2 int read4(char[] buf); */ 3 4 public class Solution extends Reader4 { 5 char[] tempBuf = new char[4]; 6 int offset = 4; 7 int maxLen = 4; 8 9 /**10 * @param buf11 * Destination buffer12 * @param n13 * Maximum number of characters to read14 * @return The number of characters read15 */16 public int read(char[] buf, int n) {17 int ind = 0;18 while (offset < maxLen && ind < n) {19 buf[ind++] = tempBuf[offset++];20 }21 if (maxLen < 4) return ind;22 23 ind = readFile(buf, ind, n);24 return ind;25 }26 27 public int readFile(char[] buf, int ind, int n) {28 int num = 4;29 while (num == 4 && ind < n) {30 num = read4(tempBuf);31 int end = Math.min(num, n - ind);32 for (offset = 0; offset < end; offset++) {33 buf[ind++] = tempBuf[offset];34 }35 }36 maxLen = num;37 return ind;38 }39 }
LeetCode-Read N Characters Given Read4 II - Call multiple times
声明：以上内容来自用户投稿及互联网公开渠道收集整理发布，本网站不拥有所有权，未作人工编辑处理，也不承担相关法律责任，若内容有误或涉及侵权可进行投诉： 投诉/举报 工作人员会在5个工作日内联系你，一经查实，本站将立刻删除涉嫌侵权内容。