首页 > 代码库 > Length of last word--LeetCode
Length of last word--LeetCode
题目:
Given a string s consists of upper/lower-case alphabets and empty space characters ‘
‘
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello
World"
,
return 5
.
思路:从尾部向前遍历,找到第一个为空格的字符,这个就是最后一个单词的长度
#include <iostream> #include <string> #include <vector> using namespace std; int LengthofLastWord(string& str) { if(str.length() == 0) return 0; int len=0,i=str.length()-1; for(;i>=0;i--) if(str[i] ==‘ ‘) break; else len++; return len; } int main() { string str("Hello world"); cout<<LengthofLastWord(str)<<endl; return 0; }
Length of last word--LeetCode
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。