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[LeetCode] Length of Last Word
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = "Hello World", return 5.
class Solution {public: int lengthOfLastWord(const char *s) { int len = strlen(s); if(len == 0) return 0; int i = len-1; int LastEnd = len-1; int LastStart = 0; while(s[i]==‘ ‘&& i>=0) { i--; } LastEnd = i; if(LastEnd == -1) return 0; while(s[i]!=‘ ‘&& i>=0) { i--; } LastStart = (i+1); return LastEnd-LastStart+1; }};
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