首页 > 代码库 > Trapping Rain Water
Trapping Rain Water
题目
Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.
For example,
Given[0,1,0,2,1,0,1,3,2,1,2,1]
, return6
.
方法
对于每一个A[i],trap water 为 min(left, right)- A[i];public int trap(int[] A) { if (A == null || A.length == 0 || A.length == 1 || A.length == 2) { return 0; } int len = A.length; int[] left = new int[len]; int[] right = new int[len]; int leftMax = 0; for (int i = 0; i < len; i++) { left[i] = leftMax; if (A[i] > leftMax) { leftMax = A[i]; } } int rightMax = 0; for (int i = len; i > 0; i--) { right[i - 1] = rightMax; if (A[i - 1] > rightMax) { rightMax = A[i - 1]; } } int sum = 0; for (int i = 0; i < len; i++) { int temp = Math.min(left[i], right[i]) - A[i]; if (temp > 0) { sum += temp; } } return sum; }
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。