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rails datagrid easyui

2024-07-10 01:38:55   232人阅读

  def new    # @foo = Foo.new    @foos = Foo.find(:all,:conditions=>["project_id = #{@project.id}"])    @foolist = @foos.map do |f|      { :id => f.id, :subject => f.subject}    end    respond_to do |format|      format.json { render :json => @foolist.to_json}    end  end

响应

[{"id":6,"subject":"test1-1"},{"id":7,"subject":"11221"},{"id":8,"subject":"1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111"}]

 

改善

  def test_json    ActiveRecord::Base.include_root_in_json = false    @foos = Foo.find(:all,:conditions=>["project_id = #{@project.id}"])    respond_to do |format|      format.json { render :json => @foos}    end  end

 


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