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Partition List
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.
You should preserve the original relative order of the nodes in each of the two partitions.
For example,
Given 1->4->3->2->5->2
and x = 3,
return 1->2->2->4->3->5
.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *partition(ListNode *head, int x)
{
if(head==NULL || head->next==NULL) return head;
ListNode* pLarge;
ListNode* pSmall;
ListNode* pMid;
if(head->val<x) pSmall=head;
else
{
pLarge=head;
pMid=head;
while(pMid->next!=NULL && pMid->next->val>=x) pMid=pMid->next;
if(pMid->next==NULL) return head;
head=pMid->next;
pMid->next=head->next;
head->next=pLarge;
pSmall=head;
}
while(true)
{
pMid=pSmall;
while(pMid->next!=NULL && pMid->next->val>=x) pMid=pMid->next;
if(pMid->next==NULL) break;
pLarge=pMid->next;
pMid->next=pLarge->next;
pLarge->next=pSmall->next;
pSmall->next=pLarge;
while(pSmall->next!=NULL && pSmall->next->val<x) pSmall=pSmall->next;
if(pSmall->next==NULL) break;
}
return head;
}
};
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *partition(ListNode *head, int x)
{
if(head==NULL || head->next==NULL) return head;
ListNode* pLarge;
ListNode* pSmall;
ListNode* pMid;
if(head->val<x) pSmall=head;
else
{
pLarge=head;
pMid=head;
while(pMid->next!=NULL && pMid->next->val>=x) pMid=pMid->next;
if(pMid->next==NULL) return head;
head=pMid->next;
pMid->next=head->next;
head->next=pLarge;
pSmall=head;
}
while(true)
{
pMid=pSmall;
while(pMid->next!=NULL && pMid->next->val>=x) pMid=pMid->next;
if(pMid->next==NULL) break;
pLarge=pMid->next;
pMid->next=pLarge->next;
pLarge->next=pSmall->next;
pSmall->next=pLarge;
while(pSmall->next!=NULL && pSmall->next->val<x) pSmall=pSmall->next;
if(pSmall->next==NULL) break;
}
return head;
}
};
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