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Gas Station
There are N gas stations along a circular route, where the amount of gas at station i is gas[i]
.
You have a car with an unlimited gas tank and it costs cost[i]
of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station‘s index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
class Solution { public: int canCompleteCircuit(vector<int> &gas, vector<int> &cost) { int N=gas.size(); int sum[N]; for(int i=0;i<N;i++) sum[i]=gas[i]-cost[i]; //check int total=0; for(int i=0;i<N;i++) total=total+sum[i]; if(total<0) return -1; //find 1st - int first=0; if(sum[first]>=0) while(sum[first]>=0) { first=(first+1)%N; if(first==0) return 0; } else while(sum[(first-1+N)%N]<0) first=(first-1+N)%N; int minvalue=http://www.mamicode.com/0; int minindex; int i=first; do { int total=0; while(sum[i]<0) { total=total+sum[i]; i=(i+1)%N; } if(total<minvalue) { minvalue=total; minindex=i; } while(sum[i]>=0) i=(i+1)%N; }while(i!=first); return minindex; } };
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