首页 > 代码库 > Binary Tree Maximum Path Sum
Binary Tree Maximum Path Sum
Given a binary tree, find the maximum path sum.
The path may start and end at any node in the tree.
For example:
Given the below binary tree,
1 / 2 3
Return 6
.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int maxPathSum(TreeNode *root) { if(root==NULL) return 0; int allmax=root->val; getmax(root,allmax); return allmax; } int getmax(TreeNode *root,int& allmax) { if(root==NULL) return 0; int line=root->val; int left=getmax(root->left,allmax); int right=getmax(root->right,allmax); if(left>right && left>=0) line+=left; if(left<right && right>=0) line+=right; int sum=root->val; if(left>=0) sum+=left; if(right>=0) sum+=right; if(allmax<sum) allmax=sum; return line; } };
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。