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Binary Tree Maximum Path Sum
Given a binary tree, find the maximum path sum.
The path may start and end at any node in the tree.
For example:
Given the below binary tree,
1 / 2 3
Return 6
.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: int maxPathSum(TreeNode *root) { int tmp = help(root); return maxval; } int help(TreeNode *root){ if(root == NULL) return 0; if(root->left == NULL && root->right == NULL){maxval = max(maxval, root->val); return root->val;} int lmax, rmax, ans, l, r, ret; lmax = rmax = ans = INT_MIN; l = r = 0; if(root->left) { l = help(root->left); lmax = max(l, l + root->val); } if(root->right) { r = help(root->right); rmax = max(r, r + root->val); } ans = max(lmax, rmax); ans = max(ans, root->val); ans = max(ans, l + r + root->val); maxval = max(ans, maxval); ret = max(l+root->val, r+root->val); ret = max(ret, root->val); return ret; } int maxval = INT_MIN;};
Binary Tree Maximum Path Sum
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