首页 > 代码库 > Java中 return 和finally

Java中 return 和finally

2024-07-05 19:28:48   227人阅读

1. 最简单的情形

    public void main(){
        String s = test();
        System.out.println("s=[" + s + "]");
    }
    
    public String test(){
        String s = "";
        try{
            System.out.println("In try");
            s += "try," ;
        }catch(Exception ex){
            System.out.println("In catch");
        }finally{
            s += "finally,";
            System.out.println("In finally");
        }
        s+="other";
        return s;
    }

输出的结果是：

In try
In finally
s=[try,finally,other]

2. 在try中加上return，那么结果是

    public String test(){
        String s = "";
        try{
            System.out.println("In try");
            s += "try," ;
            return s; //加上return
        }catch(Exception ex){
            System.out.println("In catch");
        }finally{
            s += "finally,";
            System.out.println("In finally");
        }
        s+="other";
        return s;
    }

结果是

In try
In finally
s=[try,]

说明虽然会执行finally语句，但是return的结果已经准备好了。然后才执行finally，在执行finally之前，会将返回的结果存储到不同于s的变量中，finally执行成功之后，才会返回对应的结果。因此即使在finally中对结果进行修改，也不会修改返回的结果。

3. 如果在catch中return会怎么样呢？

    public String test(){
        String s = "";
        try{
            System.out.println("In try");
            s += "try," ;
            throwException();
        }catch(NullPointerException ex){
            System.out.println("In catch");
            s += "catch,";
            return s;
        }finally{
            s += "finally,";
            System.out.println("In finally");
        }
        s+="other";
        return s;
    }
    
    public void throwException() throws NullPointerException{
        throw new NullPointerException();
    }

执行结果是：

In try
In catch
In finally
s=[try,catch,]

可见道理是一样的，也就是不管在try还是在catch中的语句中return的结果，即使在finally中进行修改，都不会改变结果。

4. return 语句先执行，还是finally先执行呢？

    public String test(){
        String s = "";
        try{
            
            System.out.println("In try");
            s += "try," ;
            throwException();
        }catch(NullPointerException ex){
            System.out.println("In catch");
            s += "catch,";
            return s += testReturn();
        }finally{
            s += "finally,";
            System.out.println("In finally");
        }
        s+="other";
        return s;
    }
    
    public String testReturn(){
        System.out.println("In Return");
        return "return,";
    }
    
    public void throwException() throws NullPointerException{
        throw new NullPointerException();
    }

结果是：

In try
In catch
In Return
In finally
s=[try,catch,return,]

也就是，return还是要比finally先执行，但是这时函数还没急着返回，只有把finally执行完才会返回。

 

总结的结果是： 

1. 不管是否有异常，finally都会执行

2. 即使try或catch中有return语句，finally仍然会执行

3. finally中语句是在return语句之前执行的，即return语句执行就决定了返回的结果

4. return语句执行完如果还有finally块，还会执行finally块，但是无法修改return语句返回的结果

 

参考资料：

http://www.cnblogs.com/ybwang/archive/2010/10/10/1847269.html


联系
我们