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1065. A+B and C (64bit)
1065. A+B and C (64bit) (20)
时间限制
100 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
HOU, Qiming
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.
Input Specification:
The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).
Sample Input:31 2 32 3 49223372036854775807 -9223372036854775808 0Sample Output:
Case #1: falseCase #2: trueCase #3: false
1 #include<stdio.h> 2 #include<math.h> 3 #include<stdlib.h> 4 #include<string.h> 5 6 int main() 7 { 8 int i, t; 9 scanf("%d", &t);10 long long a, b, c;11 for(i = 1; i <= t; i++)12 {13 scanf("%lld%lld%lld", &a, &b, &c);14 long long sum = a + b;15 if(a > 0 && b > 0 && sum < 0)16 printf("Case #%d: true\n", i);17 else if(a < 0 && b < 0 && sum >= 0)18 printf("Case #%d: false\n", i);19 else if(sum > c)20 printf("Case #%d: true\n", i);21 else22 printf("Case #%d: false\n", i);23 }24 return 0;25 }
1065. A+B and C (64bit)
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